CA Foundation · Quantitative Aptitude · Differential and Integral Calculus
The total revenue function of a firm is R(x) = 60x − 0.2x² (in ₹). The average revenue at the output where marginal revenue is zero is:
Marginal revenue is 60 − 0.4x, which is zero at x = 150. Average revenue is R/x = 60 − 0.2x, so at 150 units it equals 60 − 30 = ₹30.
- A₹30Correct
- B₹60
- C₹15
- D₹45
Explanation
MR = 60 − 0.4x = 0 gives x = 150. Average revenue = R/x = 60 − 0.2x = 60 − 30 = ₹30. The value ₹60 is the intercept of the average revenue, valid only at x = 0.
Did you get it right without looking?
One question tells you little. A timed set on Differential and Integral Calculus shows your real accuracy, how long you take and where you lose marks.
More Differential and Integral Calculus questions
- Evaluate ∫ (x + 1)² / x dx, for x > 0, where C is the constant of integration.
- The total revenue function of a firm is R(x) = 60x − 0.5x² (in ₹). The output at which marginal revenue becomes zero is:
- The profit of a Pune firm is P(x) = −x³ + 12x² + 60x − 200 (in ₹ thousand) for output x units, x > 0. The output at which profit is maximum …
- Evaluate ∫ x² log x dx.
- The area bounded by the curve y = x², the x-axis and the ordinates x = 1 and x = 3 is:
- The rate of change of revenue is R'(x) = 100 − 4x (in ₹), where x is units sold, and revenue is zero when no units are sold. The total reven…