CFA Level I Exam · Statistical Distributions for Financial Asset Prices and Returns
Normal Distribution and Z-scores for CFA Level I
Updated 7 October 2026 · Fact-checked
The normal distribution is a symmetric, bell-shaped distribution fully described by its mean and standard deviation. To solve a question, convert the value to a z-score, z = (x − μ) ÷ σ, then read the cumulative probability from a z-table. Intervals of ±1, ±2 and ±3 standard deviations are the reference ranges.
Understand Normal Distribution and Standardization (Z-scores)
The normal distribution is a continuous, bell-shaped distribution. It is symmetric around its mean, so the mean, median and mode are equal. Two numbers describe it fully: the mean (μ) and the standard deviation (σ). Skewness is 0 and kurtosis is 3 (excess kurtosis is 0).
Because it is continuous, the probability of any single exact value is zero. You only find probabilities for ranges, such as P(X ≤ 5%) or P(−2% < X < 8%). That is why the area under the curve matters.
Standardization turns any normal variable into the standard normal distribution, which has mean 0 and standard deviation 1. The z-score tells you how many standard deviations a value sits above or below the mean. A z of −1.5 means 1.5 standard deviations below the mean. Once you have z, one table serves every normal variable.
The z-table gives the cumulative probability N(z) = P(Z ≤ z). Because the curve is symmetric, N(−z) = 1 − N(z). For probabilities above a value, use 1 − N(z). For a range, subtract the two cumulative probabilities.
A useful rule of thumb gives approximate intervals around the mean: about 68% of observations lie within ±1σ, about 95% within ±2σ (more precisely ±1.96σ), about 99% within ±2.58σ, and about 99.7% within ±3σ. Keep the 99% and 99.7% figures separate: 2.58σ is the 99% interval, and 3σ is a wider interval. Also know the difference between a univariate distribution (one random variable) and a multivariate distribution (several variables together). A multivariate normal distribution is specified by the mean of each variable, each variable's variance, and the correlations (or covariances) between all pairs. Portfolio returns are often modelled this way. A linear combination of normal variables is also normal.
Key formulas to remember
- Z-score (standardization)
- z = (x − μ) ÷ σ
- Counts standard deviations from the mean. Use σ, not σ².
- Reverse standardization
- x = μ + zσ
- Use when a probability is given and you need the cutoff value.
- Symmetry of cumulative probabilities
- N(−z) = 1 − N(z)
- Lets you use positive-z tables for negative z.
- Probability above a value
- P(X > x) = 1 − N(z)
- The table gives the area to the left only.
- Probability between two values
- P(a < X < b) = N(zb) − N(za)
- Standardize both values first.
- Approximate confidence intervals
- 68%: μ ± 1σ; 95%: μ ± 1.96σ; 99%: μ ± 2.58σ
- The rule of thumb rounds 1.96σ to ±2σ. Keep 99% (±2.58σ) separate from ±3σ, which covers about 99.7%. Use 1.96 and 2.58 when exact.
- Common one-sided z values
- N(1.28) ≈ 0.90; N(1.645) ≈ 0.95; N(2.33) ≈ 0.99
- Useful for 5% and 1% tail cutoffs.
- Linear transformation of a normal variable
- If X ~ N(μ, σ²), then aX + b ~ N(aμ + b, a²σ²)
- Normal stays normal under linear combinations.
How to solve Normal Distribution and Standardization (Z-scores) questions
Use the same routine for any normal distribution question. It works for probabilities, cutoffs and confidence intervals.
- 1Write down μ and σ. Check whether the question gives variance; if so, take the square root.
- 2Identify what is wanted: a probability (area), or a value (cutoff) for a given probability.
- 3For a probability, convert each boundary to z using z = (x − μ) ÷ σ.
- 4Sketch a quick bell curve and shade the required area: left tail, right tail or middle.
- 5Find N(z) from the table. Use N(−z) = 1 − N(z) for negative z.
- 6Combine: left tail is N(z); right tail is 1 − N(z); middle is N(zb) − N(za).
- 7For a cutoff, find the z for the given probability, then compute x = μ + zσ.
- 8Check that the answer is sensible: a value above the mean should have probability above 50% to its left.
Quickest way: Shortcut with reference z-values
When to use it: Use when the question asks about 1, 2 or 3 standard deviations, or a common confidence level, so you can avoid the table.
- Compute how many σ the value is from μ: (x − μ) ÷ σ.
- If the answer is about 1, 2 or 3, use 68%, 95% or 99.7% for the two-sided area. Use 99% only with 2.58σ.
- For a one-sided tail, take the two-sided outside area and halve it. Outside 95% is 5%, so each tail is about 2.5%.
- Match the result to the three options; often only one fits. Eliminate options that break symmetry or exceed 100%.
- On the BA II Plus, there is no direct normal function in the standard Level I workflow, so rely on remembered z-values and the table values given in the exam.
Common mistakes in Normal Distribution and Standardization (Z-scores)
Using variance instead of standard deviation in the z-score.
The question gives σ² and students plug it straight in.
Fix: Always check the symbol. If you see σ² or 'variance', take the square root first.
Reading N(z) as the probability above z.
Students forget that the table gives the cumulative area to the left.
Fix: For 'greater than', calculate 1 − N(z). Sketch and shade the area before computing.
Mishandling negative z-scores.
Many tables list only positive z.
Fix: Use N(−z) = 1 − N(z). For example, if N(1.0) = 0.8413, then N(−1.0) = 0.1587.
Treating 68-95-99 as two-sided when the question is one-sided.
The rule of thumb is quoted as an interval around the mean.
Fix: For one tail, halve the outside area. About 95% inside means about 2.5% in each tail.
Assuming returns are exactly normal.
The normal is the default model, so students apply it without thought.
Fix: Remember that real returns often show fat tails and skew. The normal can understate extreme losses.
Confusing univariate and multivariate normal.
Both use the word normal.
Fix: Univariate needs a mean and variance. Multivariate also needs the correlations between each pair of variables.
Worked examples
Example 1
A fund's annual return is normally distributed with a mean of 8% and a standard deviation of 10%. Given N(1.0) = 0.8413, what is the probability that the return is below −2%? (A) 0.1587 (B) 0.3413 (C) 0.8413
Show the solution
- μ = 8%, σ = 10%, x = −2%.
- z = (−2 − 8) ÷ 10 = −1.0.
- P(X < −2%) = N(−1.0) = 1 − N(1.0).
- 1 − 0.8413 = 0.1587.
Answer: (A) 0.1587. The return is 1 standard deviation below the mean, so about 15.87% of outcomes fall below it.
Example 2
Monthly returns on a global equity index are normal with a mean of 1% and a standard deviation of 4%. Given N(1.0) = 0.8413 and N(−0.5) = 0.3085, what is the probability that the return is between −1% and 5%? (A) 0.3085 (B) 0.5328 (C) 0.8413
Show the solution
- Lower z = (−1 − 1) ÷ 4 = −0.5.
- Upper z = (5 − 1) ÷ 4 = 1.0.
- P = N(1.0) − N(−0.5).
- 0.8413 − 0.3085 = 0.5328.
Answer: (B) 0.5328. Subtract the left-tail cumulative probability from the upper cumulative probability.
Exam tips
- Questions are three-option MCQs, so sketch the curve and eliminate options that contradict the area, such as a value above the mean with probability below 50%.
- Check whether the stem gives variance or standard deviation before computing z.
- Memorize 1.645, 1.96 and 2.58 as the common cutoffs for 90%, 95% and 99% two-sided intervals, and 1.28, 1.645 and 2.33 for one-sided tails.
- Expect conceptual items too: symmetry, skewness of 0, kurtosis of 3, and what a multivariate normal needs to be specified.
- Do not spend more than about 90 seconds; with a z-table supplied in the item, the work is two lines of arithmetic.
Practice questions from Statistical Distributions for Financial Asset Prices and Returns
- A continuous uniform random variable is defined over the interval from 10 to 22. The variance of this distribution is closest to:
- An analyst estimates an option's value with a Monte Carlo simulation of 10,000 trials and obtains a standard error of 0.40. To cut the stand…
- A stock priced at 80 follows a two-period binomial tree. Each period it rises by a factor u = 1.10 or falls by a factor d = 0.90 (the up pro…
- A continuous uniform random variable X lies between 0 and 80. An analyst wants the value x such that the probability that X exceeds x is 15%…
- A stock's continuously compounded returns are 6% in the first year and -2% in the second year, with an initial price of 50. Assuming no divi…
Normal Distribution and Standardization (Z-scores) in other exams
The same ground in other exams, if you are preparing for more than one or want another angle on it.
Normal Distribution and Standardization (Z-scores): frequently asked questions
How do I calculate a z-score and probability from a z-table?
Compute z = (x − μ) ÷ σ. Look up N(z) in the table for the area to the left. For a right tail use 1 − N(z), and for a range subtract the two cumulative values.
What are the 68, 95 and 99 percent confidence intervals for a normal distribution?
About 68% of outcomes lie within one standard deviation of the mean, about 95% within 1.96 standard deviations (roughly 2), and about 99% within 2.58 standard deviations. Within 3 standard deviations the figure is about 99.7%, which is a separate, wider interval. These are two-sided intervals around the mean.
What is the difference between a univariate and a multivariate normal distribution?
A univariate normal describes one random variable with a mean and a variance. A multivariate normal describes several variables together and also needs the correlations between each pair. It is commonly used to model returns on several assets in a portfolio.
Why is the probability of an exact value zero for a normal distribution?
The distribution is continuous, so probability is an area under the curve. A single point has no width, so its area is zero. You always compute probabilities over a range.