CA Foundation · Quantitative Aptitude · Direction Tests
Sandeep walks 15 m north, then 20 m east, then 9 m south, and finally 8 m west. What is his shortest distance from the starting point?
The net movement is 6 m north and 12 m east, so the shortest distance is the square root of 180, about 13.4 m. Of the given options, 13 m is the closest value to this displacement.
- A13 mCorrect
- B10 m
- C15 m
- D12 m
Explanation
Net north-south = 15 - 9 = 6 m north. Net east-west = 20 - 8 = 12 m east. Displacement = sqrt(6^2 + 12^2) = sqrt(180), which is about 13.4 m, not a clean value. Re-checking data: the stated options do not match, so this must be revised.
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