Actuarial Mathematics for Modelling · Projecting and valuing cashflows contingent on multiple decrement events
Valuing Benefits Contingent on Decrement Events
Updated 11 October 2026 · Fact-checked
For each year, multiply the probability of being in force at the start, the probability of leaving by that specific cause, the benefit and the discount factor. Add across years. In symbols, EPV = Σ v^(t+1) · t p_x^(τ) · q_{x+t}^(j) · B. Survival uses all decrements together.
Understand Valuing Benefits Contingent on Decrement Events
A decrement is any way a life leaves a group: death, withdrawal, retirement or disability. In a multiple decrement model, a life in force can leave by one of several causes. Each cause pays its own benefit, or none. For example, a pension scheme may pay a lump sum on death, a refund on withdrawal and a pension on retirement.
To value a benefit, you need the expected present value (EPV). This is the average of the discounted benefit over all the ways the future can unfold. You do not simulate paths. You weight each possible payment by the probability that it happens, then discount it.
Two probabilities matter. First, the probability that the life is still in force at time t. This depends on all decrements, because leaving by any cause removes the life from the group. Call it t p_x^(τ). Second, the probability of leaving by the specific cause j in the next period. Multiply these two and you get the chance that a benefit for cause j is paid in that period.
You can do this with a table of lives: start with l_x^(τ) lives, record the number d^(j) leaving by each cause each year, and divide by l_x^(τ) at the end. You can also do it recursively, working backwards from the last year. The same logic extends to reserves. Thiele's equation is the continuous-time form, treating each state as a place the life can leave from.
Be clear on timing. Benefits payable at the end of the year of decrement are discounted by v^(t+1). Benefits payable immediately on decrement are handled with an integral or an approximation. Premiums are paid only while the life is in force, so they depend on survival, not on any one cause.
Key rules to remember
- Total survival probability (one year)
- p_x^(τ) = 1 − Σ_j q_x^(j)
- Here q_x^(j) is the dependent (absolute) probability of leaving by cause j in the year, so the causes add up. Do not use independent rates here unless you have converted them first.
- Probability of surviving t years
- t p_x^(τ) = p_x^(τ) × p_{x+1}^(τ) × … × p_{x+t−1}^(τ)
- In terms of lives in force, t p_x^(τ) = l_{x+t}^(τ) ÷ l_x^(τ).
- EPV of a benefit on cause j, paid at end of year of decrement
- EPV = Σ_{t≥0} v^(t+1) × t p_x^(τ) × q_{x+t}^(j) × B_{t+1}^(j)
- B_{t+1}^(j) is the benefit if the life leaves by cause j in year t+1. For several causes, sum the EPVs.
- Same EPV using a table of lives
- EPV = Σ_{t≥0} v^(t+1) × d_{x+t}^(j) × B_{t+1}^(j) ÷ l_x^(τ)
- Here d^(j) = l^(τ) × q^(j) is the expected number leaving by cause j.
- Continuous-time EPV
- EPV = ∫ from 0 to ∞ of v^t × t p_x^(τ) × μ_{x+t}^(j) × B_t dt
- Here t p_x^(τ) = exp(−∫ from 0 to t of Σ_j μ_{x+s}^(j) ds). The force μ^(j) is the transition intensity for cause j.
- One-year recursion for an EPV
- A_x = v × [ Σ_j q_x^(j) × B^(j) + p_x^(τ) × A_{x+1} ]
- Works for benefits paid at end of the year of decrement. Start at the final age, where A = 0 if cover ends.
- Policy value recursion (premium at start, benefits at end of year)
- (tV + P_t) × (1 + i) = Σ_j q_{x+t}^(j) × B^(j) + p_{x+t}^(τ) × t+1V
- Here tV is the policy value for a life in force. Benefits on decrement are the amounts paid, which may include a policy value release if the benefit is a refund.
- Thiele's equation for state i
- d/dt tV^(i) = δ × tV^(i) + P^(i) − b^(i) − Σ_{j≠i} μ_{x+t}^(ij) × ( S^(ij) + tV^(j) − tV^(i) )
- Here P^(i) is the premium rate in state i, b^(i) the benefit payment rate in state i, S^(ij) the lump sum on moving from i to j, and tV^(j) the value in the state moved to. If j is a terminal state such as death, tV^(j) = 0.
How to solve Valuing Benefits Contingent on Decrement Events questions
Use the same method for any question on benefits payable on decrements, whether it is a pension, a health policy or a unit-linked contract.
- 1List the decrements and the benefit for each one. Note whether each is paid at the end of the year or at the moment of decrement, and whether the amount changes with time.
- 2Identify the rates you are given. Check whether they are dependent (absolute) rates q^(j), independent rates q'^(j), or forces μ^(j). Convert to dependent rates if needed before using the formulas.
- 3Build a year-by-year schedule. For each year, find the probability in force at the start, then the probability of each decrement in that year, by multiplying in-force probability by q^(j).
- 4Multiply each decrement probability by its benefit, then by the discount factor for that payment date. This gives the EPV for that year and cause.
- 5Sum across years and causes. If premiums are involved, value them separately as a life-contingent annuity that is paid only while the life is in force.
- 6For a premium, set EPV of premiums equal to EPV of benefits (plus expenses if stated), and solve for P.
- 7For a reserve, use the recursion or Thiele's equation from the end of the term backwards, or value future benefits less future premiums prospectively.
- 8Check: probabilities in each year must add to one (survive plus all decrements), and the EPV must be sensible against the largest benefit.
Quickest way: Table of lives, then one discounting pass
When to use it: Use this when you are given annual decrement rates and a short term, typically three to five years, and asked for an EPV or premium.
- Start with a notional l = 1 (or 1,000 or 1,00,000) lives at the start.
- For each year write: lives in force, d^(j) for each cause, and lives surviving to the next year.
- Compute the benefit outgo for each year as Σ d^(j) × B^(j).
- Multiply each year's outgo by v^(t+1), add up, and divide by the starting lives.
- For premiums, build a second column of in-force lives at the start of each year, discount with v^t, and add to get the annuity factor.
- Divide the EPV of benefits by the annuity factor to get the premium.
Common mistakes in Valuing Benefits Contingent on Decrement Events
Using the independent (single-decrement) rate q'^(j) where the dependent rate q^(j) is needed.
The notation looks similar, and students forget that other decrements can remove the life first.
Fix: Check the notation in the question. In EPV and survival formulas use the dependent rates, which add up to 1 − p^(τ). Convert independent rates first if that is what you are given.
Using only the survival probability for one cause, for example (1 − q^d), when working out who is still in force.
Students think of the benefit cause only and forget that withdrawal also removes lives.
Fix: Always use the total survival probability p^(τ) = 1 − Σ q^(j) for the in-force population.
Discounting a benefit paid at the end of the year of decrement by v^t instead of v^(t+1).
The in-force probability is t p_x, so the index t is carried over to the discount factor.
Fix: Write the payment date beside each term. A decrement in year t+1 paid at year end is discounted for t+1 years.
Applying the premium to lives who have already left, for example discounting premiums with the decrement-year probability.
Students mix up the benefit and premium timing patterns.
Fix: Premiums at the start of a year need the probability of being in force at that time, t p_x^(τ), with discount v^t. No decrement probability enters.
Getting the signs wrong in Thiele's equation, especially the term in tV^(j) − tV^(i).
The sign convention for premiums and benefits is not stated clearly in working.
Fix: Write the equation in words first: growth in reserve = interest on reserve + premium − benefit payments − expected cost of transitions, where the cost is the lump sum plus the value in the new state minus the current value.
Treating a refund or surrender benefit as additional to the reserve release, or forgetting that a zero benefit still removes the life.
Withdrawal with no payment feels like no event.
Fix: Every decrement removes the life from the in-force group. Give it a benefit of zero in the schedule rather than leaving it out.
Worked examples
Example 1
A three-year employee benefit scheme covers a life now in force. In each year the dependent decrement rates are: year 1 death 0.01, withdrawal 0.10; year 2 death 0.02, withdrawal 0.08; year 3 death 0.03, withdrawal 0.05. A benefit of ₹5,00,000 is paid at the end of the year of death, and ₹50,000 at the end of the year of withdrawal. Interest is 5% a year. Find the EPV of the benefits per life now in force.
Show the solution
- In-force probabilities at the start of each year: year 1 = 1. Year 2 = 1 − 0.01 − 0.10 = 0.89. Year 3 = 0.89 × (1 − 0.02 − 0.08) = 0.89 × 0.90 = 0.801.
- Year 1 expected outgo: 0.01 × 5,00,000 + 0.10 × 50,000 = 5,000 + 5,000 = ₹10,000. Discount by v = 1/1.05 = 0.952381. PV = ₹9,523.81.
- Year 2 expected outgo: 0.89 × 0.02 × 5,00,000 + 0.89 × 0.08 × 50,000 = 8,900 + 3,560 = ₹12,460. Discount by v² = 0.907029. PV = ₹11,301.58.
- Year 3 expected outgo: 0.801 × 0.03 × 5,00,000 + 0.801 × 0.05 × 50,000 = 12,015 + 2,002.50 = ₹14,017.50. Discount by v³ = 0.863838. PV = ₹12,108.85.
- Add: 9,523.81 + 11,301.58 + 12,108.85 = ₹32,934.24.
Answer: The EPV of benefits is about ₹32,934 per life.
Example 2
Using the benefits and decrement rates in the previous example, a level premium P is paid at the start of each year while the life is in force, for up to three years. Find P by the equivalence principle, ignoring expenses.
Show the solution
- Premium is paid at the start of each year if the life is in force, so the probabilities are 1, 0.89 and 0.801 for years 1, 2 and 3.
- EPV of premiums = P × (1 + 0.89 v + 0.801 v²), with v = 1/1.05.
- Compute: 0.89 × 0.952381 = 0.847619. And 0.801 × 0.907029 = 0.726530. The factor is 1 + 0.847619 + 0.726530 = 2.574149 (working to six places).
- Equivalence principle: EPV premiums = EPV benefits, so P × 2.574149 = 32,934.24.
- P = 32,934.24 ÷ 2.574149 = 12,794.2 (to the nearest ₹0.1).
Answer: The level annual premium is about ₹12,794.
Exam tips
- Write the notation you are using before you start. Mark whether each rate is dependent q^(j), independent q'^(j) or a force μ^(j). Examiners give marks for clear working even when arithmetic slips.
- State the timing assumption for each benefit (end of year of decrement or immediately on decrement) in one line. If the paper does not specify, say what you assume.
- In computer-based Paper B questions, build the schedule in columns: in-force, each decrement, benefit outgo, discount factor, PV. Keep rates in one input cell so that you can change the basis and re-run.
- For Thiele questions, state the equation first, then substitute values. Show the terminal condition (such as tV = 0 at the end of the term, or at the maturity amount).
- Check that in-force probability plus all decrement probabilities equal one in each year. This catches most input errors early.
Practice questions from Projecting and valuing cashflows contingent on multiple decrement events
- In a double-decrement service table, l_x^(τ) = 10,000 lives are in service at age x. During the year, d_x^(1) = 300 leave by withdrawal and …
- A policy is in its final year, with no further premiums. At the end of the year it pays 50,000 on death, 10,000 on withdrawal and 20,000 on …
- In a multiple decrement table for active employees with two causes of exit, death (d) and withdrawal (w), the force of decrement from cause …
- A member earns an annual salary of Rs 5,00,000. Over the next year the probabilities of decrement while in service are: death 0.02 and withd…
- In a double decrement model, the force of decrement from cause 1 is a constant 0.02 per annum and from cause 2 is a constant 0.03 per annum.…
Valuing Benefits Contingent on Decrement Events: frequently asked questions
How do I find the EPV of a benefit payable on one specific decrement?
For each year, multiply the probability of being in force at the start by the probability of leaving by that cause in the year, then by the benefit and the discount factor. Add the results across all years. The in-force probability uses all decrements together.
What is the difference between dependent and independent decrement rates?
A dependent (absolute) rate is the probability of leaving by a cause in the presence of all other causes. An independent rate is the probability of leaving by that cause if no other cause operated. EPV and survival calculations need the dependent rates.
How do I calculate a premium for a contract with several decrements?
Find the EPV of all benefits on all decrements. Find the EPV of premiums as the premium times an annuity factor that uses the probability of being in force at each payment date. Set them equal, add expenses if given, and solve for the premium.
How does Thiele's equation apply to a multiple decrement model?
Treat the in-force state as state i and each decrement as a transition to a terminal state. The reserve changes by interest and premium, less benefit payments, less the expected cost of transitions at each force μ^(ij). Terminal states usually have a value of zero.