FRM Part I · FRM Exam Part I · Common Univariate Random Variables
A random variable X is normally distributed with a mean of 8 and a standard deviation of 4. Using Φ(1) = 0.8413, Φ(2) = 0.9772 and Φ(3) = 0.9987, what is P(X > 16)?
The probability is 2.28%. The value 16 lies two standard deviations above the mean of 8, so z = 2, and the upper-tail probability is 1 − 0.9772 = 0.0228. Doubling it for both tails or using the lower tail would be incorrect.
- A2.28%Correct
- B4.55%
- C15.87%
- D97.72%
Explanation
The standardized value is z = (16 − 8)/4 = 2. The upper-tail probability is 1 − Φ(2) = 1 − 0.9772 = 0.0228. The 4.55% option is the two-tailed probability, and 97.72% is the lower tail.
Did you get it right without looking?
One question tells you little. A timed set on Common Univariate Random Variables shows your real accuracy, how long you take and where you lose marks.
More Common Univariate Random Variables questions
- X is discrete uniform on the integers 1 to n. A analyst states that the variance of X is 52.25 (that is, (n^2 - 1)/12 = 52.25). What is P(X …
- A risk analyst models daily P&L of a desk as independent draws from a distribution with mean 0.5 and standard deviation 4 (in USD thousands)…
- A risk manager models the number of loan defaults in a portfolio of 10 independent loans, each with a default probability of 0.10. What is t…
- A fair six-sided die is rolled once. Let X be the number showing. Under a discrete uniform distribution on {1,2,3,4,5,6}, what is the varian…
- Defaults in a portfolio follow a Poisson distribution with a rate of 2 per year. Assuming a constant rate and independence across periods, w…
- The sum of 100 independent daily losses, each with mean 2 and standard deviation 3 (USD million), is approximated by a normal distribution u…