IAI Actuarial Core Principles · Risk Modelling and Survival Analysis · Core concepts of time series models
For a stationary MA(1) process X_t = e_t + 0.5 e_{t-1}, with e_t white noise of variance sigma^2, what is the autocorrelation at lag 1 and at lag 2?
The lag 1 autocorrelation is 0.4, from theta/(1+theta^2) = 0.5/1.25, and the lag 2 autocorrelation is zero, because an MA(1) process has autocorrelations that cut off after lag 1.
- A0.4 and 0Correct
- B0.5 and 0.25
- C0.5 and 0
- D0.8 and 0
- 0.4 and 0.16
Explanation
For MA(1) with coefficient theta, rho_1 = theta/(1+theta^2) = 0.5/1.25 = 0.4. The autocorrelation is zero for all lags beyond 1. The option 0.5 forgets the denominator; 0.5 and 0.25 treats it like an AR(1).
Did you get it right without looking?
One question tells you little. A timed set on Core concepts of time series models shows your real accuracy, how long you take and where you lose marks.
More Core concepts of time series models questions
- Which condition makes the MA(1) process X_t = e_t + θ e_{t-1} invertible?
- For an AR(1) process with phi = 0.6 and white noise variance 16, what is the variance of the two-step-ahead forecast error?
- A time series {e_t} is described as Gaussian white noise with mean zero and variance sigma squared. Which statement about this process is co…
- For a sample from an AR(2) process, which pattern of sample autocorrelation function (ACF) and partial autocorrelation function (PACF) is mo…
- Which feature of the sample partial autocorrelation function (PACF) would suggest that an AR(2) model is appropriate for a stationary series…
- X_t is a random walk with X_0 = 0 and shock variance sigma squared. For s < t, what is Corr(X_s, X_t) when s = 9 and t = 36?