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CA Foundation · Quantitative Aptitude · Probability

In a class of Chartered Accountancy aspirants, the probability that a randomly chosen student has opted for coaching in Accounting is 0.55, the probability that the student has opted for coaching in Law is 0.45, and the probability that the student has opted for at least one of the two is 0.80. What is the probability that the student has opted for both?

The probability of opting for both is 0.20. Using the addition theorem, P(A or B) equals P(A) plus P(B) minus P(A and B), so P(A and B) is 0.55 plus 0.45 minus 0.80, which gives 0.20.

  1. A0.10
  2. B0.20Correct
  3. C0.25
  4. D0.35

Explanation

By the addition theorem, P(A and B) = P(A) + P(B) - P(A or B) = 0.55 + 0.45 - 0.80 = 0.20. The value 0.10 results from subtracting 0.90 mistakenly, and 0.25 is not derivable from the data. Option 0.35 is wrongly P(A or B) - P(A) ... incorrectly taken, so it is wrong.

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