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CA Foundation · Quantitative Aptitude · Theoretical Distributions

The daily sales of a Kolkata store are normally distributed. It is known that 15.87% of days have sales above ₹68,000 and, by symmetry, 15.87% of days have sales below ₹52,000. Given that P(Z > 1) = 0.1587, what are the mean and standard deviation of daily sales?

The mean is ₹60,000 and the standard deviation is ₹8,000. Since 15.87% lies beyond one standard deviation on each side, the two limits are mean plus SD and mean minus SD, so the mean is their midpoint and the SD is half their gap.

  1. AMean ₹60,000; SD ₹8,000Correct
  2. BMean ₹60,000; SD ₹4,000
  3. CMean ₹64,000; SD ₹4,000
  4. DMean ₹60,000; SD ₹16,000

Explanation

Z = 1 is the point above which 15.87% lies, so mean + SD = 68,000 and mean − SD = 52,000. Adding gives mean = 60,000 and subtracting gives 2 SD = 16,000, so SD = 8,000. The option with SD 4,000 treats the gap of 8,000 from the mean as 2 SD, and 16,000 uses the full gap as one SD.

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