IAI Actuarial Core Principles · Actuarial Statistics
Estimators and their properties: formula sheet
Key formulas
- Estimator for a parameter
- θ̂ = g(X₁, X₂, ..., Xₙ)
- A function of the random sample. It is a random variable. Uppercase X is used.
- Estimate
- θ̂ = g(x₁, x₂, ..., xₙ)
- The same function applied to observed values. It is a single number. Lowercase x is used.
- Sample mean
- X̄ = (1 ÷ n) Σ Xᵢ
- Common estimator of the population mean μ.
- Sample variance
- S² = (1 ÷ (n − 1)) Σ (Xᵢ − X̄)²
- Common estimator of σ². Uses divisor n − 1.
- Mean and variance of X̄
- E(X̄) = μ and Var(X̄) = σ² ÷ n
- For independent observations with common mean μ and variance σ².
- Standard error
- SE(θ̂) = √Var(θ̂)
- The standard deviation of the estimator's sampling distribution.
- Bias
- bias(θ̂) = E(θ̂) − θ
- Defined from the sampling distribution. Studied further under unbiasedness.
- Bias
- bias(θ̂) = E(θ̂) − θ
- The expectation is taken over the sampling distribution of θ̂. θ is treated as fixed.
- Unbiased estimator
- E(θ̂) = θ for all θ in the parameter space
- It must hold for every possible value of θ, not just one.
- Asymptotically unbiased
- E(θ̂ₙ) → θ as n → ∞
- Equivalently, the bias tends to 0 as n → ∞.
- Expectation of sample mean
- E(X̄) = μ, Var(X̄) = σ² ÷ n
- For i.i.d. observations with mean μ and variance σ². The variance result also needs independence.
- Sample variance
- S² = Σ(Xᵢ − X̄)² ÷ (n − 1), E(S²) = σ²
- Uses i.i.d. observations with finite variance.
- Divisor n version
- E[Σ(Xᵢ − X̄)² ÷ n] = (n − 1)σ² ÷ n
- Bias is −σ² ÷ n, which tends to 0, so it is asymptotically unbiased.
- Key identity
- Σ(Xᵢ − X̄)² = ΣXᵢ² − nX̄²
- Used in the proof that S² is unbiased.
- Variance and second moment
- E(Y²) = Var(Y) + [E(Y)]²
- Used to find E(Xᵢ²) and E(X̄²).
- Bias
- bias(θ̂) = E[θ̂] − θ
- Zero for an unbiased estimator. It can be positive or negative. Always subtract θ from the expected value.
- Mean squared error
- MSE(θ̂) = E[(θ̂ − θ)²]
- The definition. It is the average squared error around the true value θ.
- MSE decomposition
- MSE(θ̂) = Var(θ̂) + [bias(θ̂)]²
- The main working formula. Prove it by writing θ̂ − θ = (θ̂ − E[θ̂]) + (E[θ̂] − θ) and expanding. The cross term has zero expectation.
- Unbiased case
- If E[θ̂] = θ, then MSE(θ̂) = Var(θ̂)
- Compare unbiased estimators by variance.
- Relative efficiency
- eff(θ̂1 relative to θ̂2) = MSE(θ̂2) ÷ MSE(θ̂1)
- Above 1 means θ̂1 is better. For two unbiased estimators this is Var(θ̂2) ÷ Var(θ̂1).
- Variance of sample mean
- Var(X̄) = σ² ÷ n
- For independent observations with common variance σ². X̄ is unbiased for μ.
- Variance estimators for a normal sample
- S² (divisor n−1): bias 0, MSE = 2σ⁴ ÷ (n−1). Divisor n: bias = −σ² ÷ n, MSE = (2n−1)σ⁴ ÷ n²
- Valid for a random sample from a normal distribution. The divisor n−1 is unbiased but the divisor n has smaller MSE.
- MSE and consistency
- MSE(θ̂) → 0 as n → ∞ implies θ̂ is consistent
- This is a sufficient condition. It is not necessary.
- Definition of consistency
- θ̂ₙ is consistent for θ if P(|θ̂ₙ − θ| > ε) → 0 as n → ∞, for every ε > 0
- This is convergence in probability, written θ̂ₙ →p θ.
- Mean squared error
- MSE(θ̂) = E[(θ̂ − θ)²] = Var(θ̂) + [bias(θ̂)]²
- Where bias(θ̂) = E(θ̂) − θ.
- Sufficient condition for consistency
- bias(θ̂ₙ) → 0 and Var(θ̂ₙ) → 0 as n → ∞ ⇒ θ̂ₙ is consistent
- Equivalent to MSE(θ̂ₙ) → 0. Sufficient, not necessary.
- Markov/Chebyshev link
- P(|θ̂ₙ − θ| > ε) ≤ MSE(θ̂ₙ) ÷ ε²
- Markov's inequality applied to (θ̂ₙ − θ)², a form of Chebyshev's inequality. This is why MSE → 0 forces convergence in probability.
- Variance of the sample mean
- Var(X̄) = σ² ÷ n
- For independent observations with common variance σ². Used to show X̄ is consistent for μ.
- Factorisation criterion
- f(x | θ) = g(t(x), θ) × h(x)
- T = t(X) is sufficient for θ if the likelihood factorises this way, with h(x) free of θ. Include any indicator for a θ-dependent support in g.
- Log-likelihood score
- U(θ) = ∂/∂θ log L(θ)
- For a regular model, E[U(θ)] = 0.
- Fisher information (two forms)
- I_n(θ) = E[(∂/∂θ log L)²] = −E[∂²/∂θ² log L]
- Both forms are equal under regularity conditions. The second form is usually quicker. Take the expectation after differentiating twice.
- Information from an iid sample
- I_n(θ) = n × I_1(θ)
- I_1 comes from a single observation. Do not forget the factor n.
- CRLB for θ
- Var(θ̂) ≥ 1 ÷ I_n(θ)
- Applies to unbiased estimators of θ under regularity conditions.
- CRLB for a function g(θ)
- Var(T) ≥ [g′(θ)]² ÷ I_n(θ)
- Applies when T is unbiased for g(θ).
- Efficiency
- e(T) = CRLB ÷ Var(T)
- Between 0 and 1 for an unbiased estimator in a regular model. It equals 1 when the bound is attained.
Quick revision
- An estimator is a random variable; an estimate is the number from one observed sample.
- Bias of θ̂ = E(θ̂) − θ. The estimator is unbiased if this is 0 for every value of θ.
- MSE(θ̂) = E[(θ̂ − θ)²] = Var(θ̂) + [bias(θ̂)]².
- For unbiased estimators, MSE equals the variance.
- A lower MSE means a better estimator; a biased estimator can beat an unbiased one on MSE.
- Sample variance with divisor n − 1 is unbiased for σ²; the divisor n version is biased.
- Consistency: the estimator converges to the true value as n → ∞. Bias → 0 and variance → 0 together are enough.
- A statistic is sufficient if it carries all the information in the sample about the parameter.
- Factorisation criterion: the likelihood splits as g(t, θ) × h(x), where t is the statistic.
- CRLB: for an unbiased estimator, Var(θ̂) ≥ 1 ÷ I(θ), where I(θ) is the Fisher information of the whole sample, under the usual regularity conditions.
- An unbiased estimator that reaches the CRLB is efficient, but many good estimators do not reach it.
- State the conditions behind any rule you quote, such as unbiasedness for the CRLB.
Common mistakes
- Using the words estimator and estimate as if they mean the same thing. Fix: Estimator is the random rule with uppercase X. Estimate is the number from data with lowercase x. Write which one you mean.
- Treating the parameter as random when finding the sampling distribution. Fix: In classical estimation the parameter is fixed. The randomness comes only from the sample.
- Writing E(X̄²) = μ² when finding E(S²). Fix: Use E(X̄²) = Var(X̄) + μ² = σ²÷n + μ². The extra σ²÷n term is what produces the n − 1.
- Saying an unbiased estimator is always close to the true value. Fix: Unbiased means correct on average only. A large variance can still give poor single estimates. Mention variance or mean squared error when comparing estimators.
- Writing MSE = variance + bias instead of bias squared. Fix: Always write MSE = Var + (bias)². Check units: variance is in squared units, so bias must be squared too.
- Comparing biased estimators by variance alone. Fix: Compute full MSE for every estimator unless both are unbiased.
- Saying an unbiased estimator is automatically consistent. Fix: Unbiased concerns the mean at fixed n. Always check that the variance also tends to zero.
- Saying a biased estimator cannot be consistent. Fix: Only bias that does not vanish matters. If bias → 0 as n → ∞ and variance → 0, the estimator is consistent.
- Using I_1(θ) instead of I_n(θ) in the bound, so the answer has no n. Fix: After finding I_1, write I_n = n × I_1 on a new line. Check that the final bound shrinks as n grows.
- Applying the CRLB to Uniform(0, θ) or another model whose range depends on θ. Fix: Always check the range of x first. If it depends on θ, say the CRLB does not apply and move on.
Exam tips
- Match notation to meaning. Uppercase X for estimators, lowercase x for estimates. Examiners award marks for this in written answers.
- When asked for a sampling distribution, state the distribution name and both parameters, not only the mean.
- Always state your assumptions, such as independence and identical distribution, before using Var(X̄) = σ²/n.
- In MCQs, check whether a quantity includes an unknown parameter. If it does, it is not a statistic.
- In the computer-based paper, compute the estimate from the data with the stated formula and show the formula in your working before the number.
- Show the identity Σ(Xᵢ − X̄)² = ΣXᵢ² − nX̄² and each expectation line by line. Marks are given for the method.
- State assumptions at the start, for example independent and identically distributed with finite variance.
- In MCQs on linear estimators, check whether the weights sum to 1 before anything else.