CMA Foundation · Fundamentals of Business Mathematics and Statistics
Time and Distance: formula sheet
Key formulas
- Basic relation
- Speed = Distance ÷ Time
- Use consistent units. Distance = Speed × Time and Time = Distance ÷ Speed follow from it.
- km/hr to m/sec
- x km/hr = x × 5/18 m/sec
- Use when distance is in metres or time is in seconds.
- m/sec to km/hr
- y m/sec = y × 18/5 km/hr
- Reverse of the above.
- Average speed (general)
- Average speed = Total distance ÷ Total time
- Works for every case.
- Average speed, equal distances
- Average speed = 2xy ÷ (x + y)
- Only for two equal distances at speeds x and y.
- Same distance, different speeds
- Time ratio = inverse of speed ratio
- If speeds are in ratio a : b, times are in ratio b : a.
- Average speed, equal times
- Average speed = (x + y) ÷ 2
- Only when equal time is spent at speeds x and y.
- Relative speed, opposite directions
- Relative speed = S₁ + S₂
- Use when bodies move towards each other or away from each other.
- Relative speed, same direction
- Relative speed = S₁ − S₂ (S₁ > S₂)
- Use when the faster body chases or overtakes the slower one.
- Time to meet or overtake
- Time = Gap to be covered ÷ Relative speed
- The gap is the initial distance between them, or the sum of lengths for trains crossing.
- km/h to m/s
- x km/h = x × 5/18 m/s
- Use when distance is in metres and time in seconds.
- m/s to km/h
- y m/s = y × 18/5 km/h
- Use when the answer must be in km/h.
- Distance covered by each body at meeting
- Distance₁ : Distance₂ = S₁ : S₂
- Both bodies travel for the same time before meeting, so distances are in the ratio of speeds.
- Basic relation
- Time = Distance ÷ Speed
- Keep distance and speed in matching units (metres with m/s, km with km/hr).
- Train crossing a pole or standing person
- Distance = Length of train
- Time = length of train ÷ speed of train.
- Train crossing a platform or bridge
- Distance = Length of train + Length of platform
- The same rule applies to bridges and tunnels.
- km/hr to m/s
- x km/hr = x × 5/18 m/s
- Example: 72 km/hr = 72 × 5/18 = 20 m/s.
- m/s to km/hr
- y m/s = y × 18/5 km/hr
- Example: 10 m/s = 36 km/hr.
- Two trains in opposite directions
- Relative speed = S1 + S2
- Time to cross = (L1 + L2) ÷ (S1 + S2).
- Two trains in the same direction
- Relative speed = S1 − S2 (S1 > S2)
- Time to cross = (L1 + L2) ÷ (S1 − S2).
- Train passing a moving person
- Relative speed = train speed ± person speed
- Subtract if moving the same way, add if moving opposite. Distance is the train's length only.
- Downstream speed
- Downstream speed (x) = u + v
- u = speed of boat in still water, v = speed of stream. Boat and stream move in the same direction.
- Upstream speed
- Upstream speed (y) = u − v
- Boat moves against the stream. Needs u > v for real upstream motion.
- Speed of boat in still water
- u = (x + y) ÷ 2
- Average of downstream and upstream speeds.
- Speed of stream
- v = (x − y) ÷ 2
- Half the difference of downstream and upstream speeds.
- Distance, speed, time
- Distance = Speed × Time; Time = Distance ÷ Speed
- Apply separately for each direction, using the matching speed.
- Average speed for a round trip over the same distance
- Average speed = 2xy ÷ (x + y)
- Total distance ÷ total time. Do not take the simple average of x and y.
- Distance ratio in a race
- Distance of A ÷ Distance of B = Speed of A ÷ Speed of B
- Valid because both run for the same time.
- A beats B by d metres in a race of L metres
- When A runs L, B runs (L − d). So Speed A : Speed B = L : (L − d)
- B is d metres behind at the moment A finishes.
- A beats B by t seconds
- Distance B covers in t seconds = distance by which A beats B
- Use B's speed to convert time to distance, or distance to time.
- Head start
- Distance run by the runner with the head start = race length − head start; the other runner runs the full race length
- The head start is measured from the start line, so the runner with it runs a shorter distance.
- Circular track, same direction
- Time to meet = track length ÷ (faster speed − slower speed)
- Applies when both start together from the same point.
- Circular track, opposite directions
- Time to meet = track length ÷ (sum of speeds)
- Applies when both start together from the same point.
- Meeting again at the starting point
- Time = LCM of the times each runner takes for one lap
- Use when the question asks when both are back at the start together.
- Unit conversion
- km/h × 5/18 = m/s
- Convert before using lap length in metres.
Quick revision
- Distance = speed × time.
- km/h to m/s: multiply by 5/18. m/s to km/h: multiply by 18/5.
- At constant distance, speed and time are inversely proportional.
- Average speed = total distance ÷ total time.
- For equal distances at speeds x and y, average speed = 2xy ÷ (x + y).
- Opposite directions: relative speed = sum of speeds. Same direction: difference.
- A train crossing a pole or a person covers its own length.
- A train crossing a platform or another train covers the sum of the lengths.
- Downstream speed = u + v. Upstream speed = u − v.
- Still-water speed = (downstream + upstream) ÷ 2. Stream speed = (downstream − upstream) ÷ 2.
- On a circular track, bodies in opposite directions meet after track length ÷ sum of speeds.
- Always check units before calculating.
Common mistakes
- Taking the simple average of two speeds as the average speed when distances are equal Fix: Use total distance ÷ total time, or 2xy ÷ (x + y). For equal distances, the result is less than the simple average when the speeds differ.
- Multiplying by 18/5 when converting km/hr to m/sec Fix: Remember that m/sec numbers are smaller. So km/hr to m/sec uses 5/18, which reduces the number.
- Adding speeds when the bodies move in the same direction. Fix: Check the sketch first. Same direction means subtract. Opposite means add.
- Forgetting to convert km/h to m/s when lengths are in metres. Fix: Before dividing, write the units of gap and speed side by side. If they differ, convert using 5/18.
- Using only the train's length when crossing a platform. Fix: For platforms and bridges, always write distance as train length + platform length.
- Forgetting to convert km/hr to m/s. Fix: Convert speed first using × 5/18 before writing any equation.
- Adding the stream speed when going upstream, or subtracting it when going downstream. Fix: Say it in words first: with the stream means add, against the stream means subtract.
- Using the average of x and y as the average speed of a round trip. Fix: Use total distance ÷ total time, which gives 2xy ÷ (x + y) for equal distances.
- Using the beat distance as B's total distance. Fix: B runs L − d when A runs L. The beat is only the gap left.
- Adding speeds for runners moving in the same direction. Fix: Same direction means subtract speeds. Opposite direction means add.
Exam tips
- Most questions are one or two steps. Spot whether the question is a conversion, a direct S-D-T find, or an average speed question.
- If distances are equal and the options include the simple average, that option is usually a trap.
- Convert units before doing anything else. Many wrong options come from unconverted units.
- Use ratio thinking for 'speed increases by' or 'time reduces by' questions. It saves calculation time.
- Since there is no negative marking, attempt every question. Eliminate options outside the speed range and guess from the rest.
- Read the direction words carefully. "Towards each other", "opposite" and "crossing" mean add. "Overtakes", "chases" and "same direction" mean subtract.
- Check the unit of the answer asked: seconds, minutes or hours. The options are often built to catch a missed conversion.
- In train problems, ask whether the other object is a pole, a platform or another train. This decides the gap.