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FRM Exam Part I · Multivariate Random Variables

Bivariate and Multivariate Normal Distributions for FRM Part I

Updated 11 October 2026 · Fact-checked

A bivariate normal distribution describes two normal variables with a given correlation. Each variable is normal on its own, and any weighted sum of them is normal. To solve questions, use the conditional mean and variance formulas, or the portfolio variance formula, then standardise and read the normal table.

Understand Bivariate Normal and Other Multivariate Distributions

Start with one normal variable. It is fixed by a mean and a standard deviation. Now take two normal variables, such as the returns on two assets. To describe them together you need five numbers: two means, two standard deviations and one correlation, ρ. That set defines the bivariate normal distribution.

The multivariate normal extends this to n variables. It is fixed by a mean vector and a covariance matrix. The diagonal of the matrix holds the variances. The off-diagonal cells hold the covariances. Covariance = ρ × σx × σy.

The distribution has useful properties. Every marginal distribution is normal. Every linear combination of the variables is normal, so a portfolio of jointly normal returns is normal. Conditional distributions are also normal. If the variables are jointly normal and uncorrelated, they are independent. This last rule does not hold for general distributions.

Correlation shapes the joint behaviour. With ρ = 0 the scatter plot is a round cloud. As ρ rises towards 1, the cloud stretches into a tilted ellipse along a line. Knowing one variable then tells you more about the other. The conditional mean shifts by an amount proportional to ρ, and the conditional variance shrinks by the factor (1 − ρ²).

Know the limits. Two variables can each be normal without being jointly normal. Joint normality is an extra assumption. Real asset returns often show fat tails and tail dependence, meaning extreme losses tend to arrive together. Under the bivariate normal with |ρ| < 1, extremes show no such asymptotic dependence. Distributions such as the multivariate t, or mixtures, allow joint extremes. This is why the normal model can understate joint tail risk.

Key formulas to remember

Covariance from correlation
Cov(X, Y) = ρ × σx × σy
Off-diagonal entry of the covariance matrix. ρ is between −1 and 1.
Conditional mean of Y given X = x
E(Y | X = x) = μy + ρ × (σy ÷ σx) × (x − μx)
Linear in x. The slope ρσy/σx is the regression slope of Y on X.
Conditional variance of Y given X = x
Var(Y | X = x) = σy² × (1 − ρ²)
Does not depend on x. Take the square root for the standard deviation.
Linear combination of two jointly normal variables
aX + bY ~ Normal(aμx + bμy, a²σx² + b²σy² + 2abρσxσy)
Used for portfolio return and risk. Watch the sign of ρ.
Standardisation
Z = (W − mean) ÷ standard deviation
Convert to a standard normal to find probabilities.
Multivariate normal parameters
X ~ N(μ, Σ), where μ is the mean vector and Σ is the covariance matrix
Σ is symmetric. Any linear combination wᵀX is normal with mean wᵀμ and variance wᵀΣw.
Independence rule
For jointly normal X and Y: ρ = 0 ⇔ X and Y are independent
Holds only under joint normality, not for marginally normal variables in general.

How to solve Bivariate Normal and Other Multivariate Distributions questions

Use this method for any question on bivariate or multivariate normal variables.

  1. 1Write down the given parameters: both means, both standard deviations (not variances) and the correlation. Convert variances to standard deviations if needed.
  2. 2Confirm the variables are jointly normal. If the question only says each is normal, you cannot assume the joint properties.
  3. 3Identify what is asked: a conditional mean or variance, a portfolio mean or variance, a probability, or a property statement.
  4. 4For a conditional question, apply E(Y | X = x) = μy + ρ(σy/σx)(x − μx) and Var = σy²(1 − ρ²).
  5. 5For a portfolio or linear combination, compute the mean from the weights, then the variance with the 2abρσxσy term.
  6. 6For a probability, standardise with Z = (value − mean) ÷ standard deviation and read the normal table. Use the conditional or the combined distribution, not the original one.
  7. 7Check the result: the conditional variance should be no larger than the original, and the portfolio standard deviation should not exceed the weighted sum of standard deviations.

Quickest way: Standardise first, then plug into the formula

When to use it: Use this when you have about two minutes per question and the numbers are given directly.

  1. Compute the standardised gap (x − μx) ÷ σx first. Then the conditional mean is μy + ρ × σy × that gap.
  2. For conditional standard deviation, compute σy × √(1 − ρ²). Memorise: ρ = 0.6 gives 0.8, ρ = 0.8 gives 0.6, ρ = 0.5 gives about 0.866.
  3. For portfolio variance, work in percentage points squared (such as 20² = 400) to avoid decimals, then take the square root at the end.
  4. Eliminate options with a logic check. Positive ρ pushes the conditional mean in the same direction as the shift in X. The conditional standard deviation must be below σy when ρ ≠ 0.

Common mistakes in Bivariate Normal and Other Multivariate Distributions

  • Using variance instead of standard deviation in the conditional mean formula.

    Questions often give variances, and the formula looks similar to the covariance formula.

    Fix: Take square roots first. The slope is ρ × σy ÷ σx, using standard deviations.

  • Forgetting the square on ρ in the conditional variance, writing σy²(1 − ρ).

    The conditional mean uses ρ alone, so students carry that over.

    Fix: Remember it as σy²(1 − ρ²). Sanity check: ρ = 1 should give zero variance.

  • Assuming that zero correlation means independence for any two normal variables.

    The rule is true for jointly normal variables and gets over-generalised.

    Fix: State the condition: the variables must be jointly normal. Marginal normality alone is not enough.

  • Assuming two normal marginals make a bivariate normal.

    Students treat joint normality as automatic once each variable is normal.

    Fix: Joint normality is a separate assumption. It needs every linear combination to be normal.

  • Dropping the covariance term, or using the wrong sign, in portfolio variance.

    Rushing under time pressure, or treating a short position as a positive weight.

    Fix: Always write a²σx² + b²σy² + 2abρσxσy. Use negative weights for short positions and let the sign of ab carry through.

  • Believing the normal model captures joint extreme losses.

    The model is so common that its limits are forgotten.

    Fix: Recall that the bivariate normal with |ρ| < 1 has no asymptotic tail dependence. Fat-tailed alternatives such as the multivariate t allow joint extremes.

Worked examples

Example 1

Returns on assets X and Y are jointly normal. X: mean 8%, standard deviation 20%. Y: mean 6%, standard deviation 15%. The correlation is 0.6. Given that X = 20%, what are the conditional mean and standard deviation of Y? Options: A) mean 11.4%, sd 12.0%; B) mean 9.6%, sd 12.0%; C) mean 11.4%, sd 15.0%; D) mean 12.0%, sd 9.0%.

Show the solution
  1. Conditional mean = μy + ρ(σy ÷ σx)(x − μx).
  2. ρ × σy ÷ σx = 0.6 × 15 ÷ 20 = 0.45.
  3. x − μx = 20 − 8 = 12, so the shift is 0.45 × 12 = 5.4.
  4. Conditional mean = 6 + 5.4 = 11.4%.
  5. Conditional variance = σy²(1 − ρ²) = 225 × (1 − 0.36) = 225 × 0.64 = 144.
  6. Conditional standard deviation = √144 = 12%.

Answer: Option A: conditional mean 11.4% and conditional standard deviation 12.0%.

Example 2

Using the same assets, a portfolio holds 60% in X and 40% in Y. What is the probability that the portfolio return is below zero? Use Φ(−0.44) ≈ 0.330.

Show the solution
  1. Portfolio mean = 0.6 × 8 + 0.4 × 6 = 4.8 + 2.4 = 7.2%.
  2. Variance = 0.6² × 20² + 0.4² × 15² + 2 × 0.6 × 0.4 × 0.6 × 20 × 15.
  3. First term: 0.36 × 400 = 144. Second term: 0.16 × 225 = 36.
  4. Third term: 2 × 0.6 × 0.4 = 0.48; 0.48 × 0.6 = 0.288; 0.288 × 300 = 86.4.
  5. Variance = 144 + 36 + 86.4 = 266.4. Standard deviation = √266.4 ≈ 16.32%.
  6. Because X and Y are jointly normal, the portfolio return is normal.
  7. Z = (0 − 7.2) ÷ 16.32 ≈ −0.44.
  8. P(return < 0) = Φ(−0.44) ≈ 0.330.

Answer: The probability of a negative portfolio return is about 33%.

Exam tips

  • Expect questions that give variances in one place and standard deviations in another. Underline what is given before you start.
  • The conditional mean and conditional variance formulas are the most tested items. Practise them until you can write them from memory.
  • Property questions use traps such as 'uncorrelated implies independent' and 'normal marginals imply normal joint'. Look for the words 'jointly normal'.
  • On portfolio questions, compute the variance in percentage points squared, then take the square root once. This avoids rounding errors.
  • On conceptual questions about tails, remember that the normal model understates joint extremes, and that the multivariate t is a common fat-tailed alternative.

Practice questions from Multivariate Random Variables

Bivariate Normal and Other Multivariate Distributions: frequently asked questions

What is the conditional mean in a bivariate normal distribution?

It is the expected value of Y given X = x. The formula is μy + ρ(σy ÷ σx)(x − μx). It is a straight line in x, so the best prediction of Y moves in proportion to the gap between x and its mean.

How does correlation affect a joint normal distribution?

Correlation sets the tilt and thinness of the elliptical cloud of outcomes. The higher |ρ| is, the more one variable tells you about the other. The conditional variance falls by the factor (1 − ρ²), and portfolio variance rises with ρ for long positions.

Does zero correlation mean independence for normal variables?

Only if the two variables are jointly normal. In that case ρ = 0 means independent. If each is only normal on its own, zero correlation does not guarantee independence.

What are the key properties of the multivariate normal distribution?

It is fully described by a mean vector and a covariance matrix. Its marginals and conditionals are normal, and any linear combination of its components is normal. Uncorrelated components are independent.

Why is the normal distribution a weak model for joint extreme losses?

Real markets show fat tails and extremes that occur together. The bivariate normal with |ρ| < 1 has no asymptotic tail dependence, so it tends to understate joint extreme events. Alternatives such as the multivariate t allow for them.