Skip to content

IAI Actuarial Core Principles · Actuarial Statistics · Confidence intervals and prediction intervals

A 95% confidence interval for a mean is calculated from a sample with known sigma. If the sample size is multiplied by 4 and the confidence level and sigma are unchanged, what happens to the expected width of the interval?

The width is halved. The interval width is proportional to one over the square root of the sample size, so quadrupling n doubles the square root and halves the width.

  1. AIt is halvedCorrect
  2. BIt is quartered
  3. CIt is unchanged
  4. DIt is doubled
  5. It is reduced to one third

Explanation

Width = 2 z sigma/sqrt(n). Multiplying n by 4 multiplies sqrt(n) by 2, so the width is divided by 2. Quartering would require n to be 16 times larger.

Did you get it right without looking?

One question tells you little. A timed set on Confidence intervals and prediction intervals shows your real accuracy, how long you take and where you lose marks.

More Confidence intervals and prediction intervals questions