CA Foundation · Quantitative Aptitude · Probability
A bag contains 5 red balls, 3 blue balls and 2 green balls. If one ball is drawn at random, what is the probability that it is neither red nor green?
The probability that the drawn ball is neither red nor green equals the number of blue balls divided by the total number of balls. There are 3 blue balls out of 10 total, giving a probability of 3/10.
- A3/10Correct
- B1/4
- C7/10
- D2/5
Explanation
Total balls = 5 + 3 + 2 = 10. Balls that are neither red nor green = blue balls = 3. Probability = 3/10. Option 1 is correct. The distractor 7/10 comes from adding red and green incorrectly; 1/4 and 2/5 are other common wrong fractions.
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