Skip to content

CMA Intermediate · Management Accounting · Decision Theory

A Chennai firm has three alternatives with payoffs (Rs. thousand) under two states of nature: Alternative X: 80 (Boom), 20 (Slump); Y: 60 (Boom), 40 (Slump); Z: 50 (Boom), 45 (Slump). Probability of Boom is 0.4 and Slump is 0.6. Which alternative has the highest expected monetary value (EMV) and what is it?

Alternative Y has the highest EMV of Rs. 48 thousand. Weighting payoffs by probabilities gives X 44, Y 48 and Z 47. Since Y yields the largest probability-weighted payoff, it is chosen under the EMV criterion.

  1. AX with EMV Rs. 44 thousand
  2. BY with EMV Rs. 48 thousandCorrect
  3. CZ with EMV Rs. 47 thousand
  4. DY with EMV Rs. 50 thousand

Explanation

EMV(X) = 0.4x80 + 0.6x20 = 32+12 = 44. EMV(Y) = 24+24 = 48. EMV(Z) = 20+27 = 47. The highest is Y at 48. Z is close but lower; using equal probabilities would give Y 50, which is wrong here.

Did you get it right without looking?

One question tells you little. A timed set on Decision Theory shows your real accuracy, how long you take and where you lose marks.

More Decision Theory questions