Skip to content

CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations

A committee of 3 members is to be chosen from 8 employees of Sharma Traders. In how many ways can the committee be chosen?

The committee can be chosen in 56 ways, because selection of 3 from 8 without regard to order is 8C3 = 56. The figure 336 is the permutation 8P3, which wrongly treats different orders of the same members as different committees.

  1. A24
  2. B56Correct
  3. C336
  4. D40320

Explanation

Order does not matter, so use 8C3 = (8×7×6)/(3×2×1) = 56. The value 336 is 8P3, which wrongly counts the order of selection.

Did you get it right without looking?

One question tells you little. A timed set on Permutation and Combinations shows your real accuracy, how long you take and where you lose marks.

More Permutation and Combinations questions