Skip to content

CA Foundation · Quantitative Aptitude · Permutations and Combinations

A company in Hyderabad has 6 managers and 4 analysts. A committee of 4 is to be formed with at most 1 analyst. In how many ways can this be done?

The committee can be formed in 95 ways, by adding the cases of no analyst (15 ways) and exactly one analyst (80 ways).

  1. A135Correct
  2. B210
  3. C15
  4. D120

Explanation

At most 1 analyst means 0 or 1 analyst. With 0 analysts: 6C4 = 15. With 1 analyst: 4C1 x 6C3 = 4 x 20 = 80. Total = 15 + 80 = 95. Check by complement: total 10C4 = 210; with 2 analysts 6C2 x 4C2 = 90... that is 15 x 6 = 90; with 3 analysts 4C3 x 6 = 24; with 4 analysts 1; sum 115; 210 - 115 = 95. So correct is 95, and no option matches.

Did you get it right without looking?

One question tells you little. A timed set on Permutations and Combinations shows your real accuracy, how long you take and where you lose marks.

More Permutations and Combinations questions