CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations
A company in Pune has 8 candidates shortlisted and must choose a Manager, an Accountant and a Cashier, each from a different candidate. How many different ways can these three posts be filled?
The posts can be filled in 336 ways. Because the three posts are different, order matters, so we count permutations of 3 chosen from 8 distinct candidates: 8P3 = 8×7×6 = 336.
- A56
- B120
- C336Correct
- D512
Explanation
The posts are different, so order matters: 8P3 = 8×7×6 = 336. The option 56 is 8C3, which ignores the distinct posts. The option 512 is 8³, which wrongly allows one person to hold several posts.
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