CA Foundation · Quantitative Aptitude · Probability
A game at a Jaipur fair costs Rs 20 to play. A player tosses two fair coins and receives Rs 50 if both show heads, Rs 20 if exactly one shows head, and nothing if both show tails. What is the player's expected net gain per play?
The expected net gain is Rs 2.50. The expected payout is 50 times 1/4 plus 20 times 1/2, which equals Rs 22.50. Subtracting the Rs 20 entry fee leaves a positive expected gain of Rs 2.50 per play.
- ARs 2.50Correct
- BRs 0
- CRs -7.50
- DRs 7.50
Explanation
P(2H)=1/4, P(1H)=1/2, P(0H)=1/4. Expected payout = 50(1/4)+20(1/2)+0 = 12.5+10 = 22.5. Net gain = 22.5 - 20 = Rs 2.50. Rs 22.50 would be wrongly ignoring the entry fee.
Did you get it right without looking?
One question tells you little. A timed set on Probability shows your real accuracy, how long you take and where you lose marks.
More Probability questions
- For two events A and B, P(A) = 0.6, P(B) = 0.5 and P(A ∩ B) = 0.3. What is P(B | A)?
- Two fair dice are rolled together. What is the probability that the sum of the numbers shown is greater than 10?
- For two events A and B, P(A) = 0.6, P(B) = 0.5 and P(A and B) = 0.3. Which statement is correct?
- In a financial institution, the probability that a loan application is approved by the manager is 0.7. If the application is approved by the…
- A box contains 4 defective and 6 good bulbs. Two bulbs are drawn one after another without replacement. Given that the second bulb is good, …
- A number is chosen at random from the integers 1 to 60. What is the probability that it is divisible by 4 or by 6 but not by both?