CA Foundation · Quantitative Aptitude · Permutations and Combinations
A hospital in Nagpur has 9 doctors. The administrator must form a panel of 4 doctors in which one particular senior doctor, Dr. Mehta, is always included. In how many ways can the panel be formed?
The number of panels is 56. Since Dr. Mehta must be on the panel, only the remaining 3 places need to be filled from the other 8 doctors, giving 8C3 = 56 ways.
- A56Correct
- B84
- C126
- D70
Explanation
Dr. Mehta is fixed, so the remaining 3 members are chosen from the other 8 doctors: 8C3 = 56. The option 126 is 9C4, which ignores the condition. The option 70 is 8C4, which wrongly picks 4 from the 8 others.
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