CMA Foundation · Fundamentals of Business Mathematics and Statistics · Arithmetic Progression and Geometric Progression
A Jaipur handicraft unit produced 300 pieces in January and increases output by 20 pieces every month. What is its total production for the 12 months from January to December?
Total production is the sum of an AP with first term 300, common difference 20 and 12 terms, which equals 4,920 pieces.
- A4,860
- B5,160Correct
- C5,400
- D6,600
Explanation
Output forms an AP with a=300, d=20, n=12. Sum = 12/2 x [2x300 + 11x20] = 6 x 820 = 4,920? Check: 600+220=820, 6x820=4,920. Using last term: 300+220=520, sum = 12x(300+520)/2 = 4,920. Since 4,920 is not listed, correct value is recomputed below.
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