CMA Final · Strategic Cost Management · Simulation
A linear congruential generator uses X(n+1) = (5 × X(n) + 3) mod 16, with seed X(0) = 7. What is the third generated number, X(3)?
The third number is 8. Starting from seed 7, the first value is 38 mod 16 = 6, the second is 33 mod 16 = 1, and the third is 8 mod 16 = 8. Each value comes from applying the formula to the previous one.
- A8Correct
- B6
- C1
- D3
Explanation
X1 = (5×7+3) mod 16 = 38 mod 16 = 6. X2 = (5×6+3) mod 16 = 33 mod 16 = 1. X3 = (5×1+3) mod 16 = 8. Choosing 1 would stop one step early at X2.
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