Skip to content

CA Foundation · Quantitative Aptitude · Theoretical Distributions

A Mumbai bank finds that 20% of loan applications are rejected. Of 5 independent applications, what is the probability that at least one is rejected? (Use 0.8^5 = 0.32768.)

The probability is 0.67232. Use the complement: the chance that no application is rejected is 0.8^5 = 0.32768, so the chance of at least one rejection is 1 − 0.32768 = 0.67232. The figure 0.32768 is the probability of no rejection.

  1. A0.32768
  2. B0.67232Correct
  3. C0.2
  4. D0.99968

Explanation

P(at least one rejected) = 1 − P(none rejected) = 1 − 0.8^5 = 1 − 0.32768 = 0.67232. The value 0.32768 is the probability that none is rejected, the complement. The value 0.99968 is wrongly using 1 − 0.2^5.

Did you get it right without looking?

One question tells you little. A timed set on Theoretical Distributions shows your real accuracy, how long you take and where you lose marks.

More Theoretical Distributions questions