CA Foundation · Quantitative Aptitude · Permutations and Combinations
A shop in Indore displays 9 flags in a row: 4 identical saffron, 3 identical white and 2 identical green. How many different displays are possible?
The answer is 1260. With 9 flags of which 4, 3 and 2 are identical, the displays number 9!/(4!·3!·2!) = 362880/288 = 1260. Ignoring identical flags would give 9! which is far too large.
- A1260Correct
- B362880
- C15120
- D2520
Explanation
Number of displays = 9!/(4!·3!·2!) = 362880/(24·6·2) = 362880/288 = 1260. Option 362880 treats all flags as different.
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