IAI Actuarial Core Principles · Economic Modelling · Role of insurance in reducing or removing risk
An insurer pools n independent policies, each with the same loss distribution of mean m and standard deviation s. Which statement about the loss per policy is correct as n increases?
With independent identical policies, the average loss per policy keeps mean m, but its standard deviation is s divided by the square root of n. Risk per policy therefore diminishes as the pool grows, which is the basis of pooling, although the total risk still grows.
- AIts standard deviation falls in proportion to 1/n
- BIts mean falls in proportion to 1/sqrt(n)
- CIts standard deviation stays at s because losses are independent
- DIts standard deviation falls in proportion to 1/sqrt(n) while the mean stays at mCorrect
- Both its mean and standard deviation rise in proportion to sqrt(n)
Explanation
Average loss per policy has mean m and variance s^2/n, so standard deviation s/sqrt(n). Option A uses 1/n, which would apply to variance, not standard deviation.
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