IAI Actuarial Core Principles · Risk Modelling and Survival Analysis · Core concepts of time series models
For the MA(1) process X_t = e_t + 0.5 e_{t-1}, where e_t is white noise with variance sigma^2, what is the autocorrelation at lag 1?
The lag-1 autocorrelation is 0.4. For an MA(1) process, rho_1 equals theta divided by (1 + theta squared), which is 0.5 divided by 1.25. The value is not equal to theta itself, and all autocorrelations beyond lag 1 are zero.
- A0.5
- B0.4Correct
- C0.25
- D0.8
- 0
Explanation
For MA(1) with parameter theta, rho_1 = theta/(1+theta^2). Here this is 0.5/(1+0.25) = 0.5/1.25 = 0.4. Choosing 0.5 uses theta itself, which is the common mistake, and the autocorrelation is zero beyond lag 1.
Did you get it right without looking?
One question tells you little. A timed set on Core concepts of time series models shows your real accuracy, how long you take and where you lose marks.
More Core concepts of time series models questions
- A stationary AR(1) model is X_t - 50 = 0.6(X_{t-1} - 50) + e_t, with white noise variance 16. The latest observation is x_100 = 60. What is …
- Let e_t be white noise with variance 9. A process is defined by Y_t = e_t + 0.4 e_{t-1}. Using the autocorrelation at lag 1 of this process,…
- A stationary, zero-mean AR(2) process X_t = 0.5 X_{t-1} + 0.2 X_{t-2} + e_t is considered. What is the autocorrelation at lag 1, rho_1?
- An actuary fits an ARIMA(1,1,0) model to monthly claim counts. Which statement about the model is correct?
- A time series follows the process X_t = μ + e_t + θ e_{t-1}, where e_t is white noise with variance σ². Which statement about the autocorrel…
- A time series X_t follows the model X_t = 0.6 X_{t-1} + e_t - 0.4 e_{t-1}, where e_t is white noise. Which description of this process is co…