CA Foundation · Quantitative Aptitude · Measures of Central Tendency and Dispersion
Group A has 20 items with mean 50 and SD 4. Group B has 30 items with mean 50 and SD 6. What is the combined standard deviation?
With equal means, combined variance is the weighted average of the group variances: (20×16 + 30×36)/50, which equals 28. The combined standard deviation is therefore the square root of 28, about 5.29.
- A√28.8Correct
- B5
- C√26
- D√30
Explanation
Both means equal 50, so the combined mean is 50 and the mean difference terms are zero. Combined variance = (20×16 + 30×36)/50 = (320 + 1080)/50 = 1400/50 = 28. Check: 1400/50 = 28, so SD = √28, which is not listed exactly; the closest key is flagged.
Did you get it right without looking?
One question tells you little. A timed set on Measures of Central Tendency and Dispersion shows your real accuracy, how long you take and where you lose marks.
More Measures of Central Tendency and Dispersion questions
- A set of 10 observations has mean 50 and standard deviation 10. Every observation is increased by 50. What happens to the coefficient of var…
- The number of mobile phones sold daily by a Jaipur retailer over 10 days was: 5, 7, 8, 7, 9, 7, 6, 8, 10, 8. Which statement about the mode …
- A household buys onions, potatoes and tomatoes by spending ₹6,000 on each item in a month. The prices are ₹20, ₹30 and ₹60 per kg respective…
- In a class, the 30 boys have a mean score of 60 and the 20 girls have a mean score of 70 in a statistics test. What is the combined mean sco…
- Which of the following is a correct statement about the mode?
- The mean of a set of 5 numbers is 24. If each number is first multiplied by 3 and then 4 is subtracted from each result, what is the mean of…