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CA Foundation · Quantitative Aptitude · Permutations and Combinations

How many 3-digit even numbers can be formed using the digits 1, 2, 3, 4, 5, 6 without repeating any digit?

The answer is 60. The units place must be even, giving 3 choices (2, 4 or 6). The tens place then has 5 choices and the hundreds place 4 choices, so the total is 3 × 5 × 4 = 60 numbers.

  1. A60Correct
  2. B120
  3. C40
  4. D90

Explanation

The units digit must be 2, 4 or 6: 3 choices. The tens digit can be any of the remaining 5 digits and the hundreds digit any of the remaining 4. Total = 3×5×4 = 60. The figure 120 is 6P3, which ignores the even condition.

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