CA Foundation · Quantitative Aptitude · Ratio and Proportion, Indices and Logarithms
If log₃ (x − 2) + log₃ (x + 4) = 2, then x equals:
None of the options satisfies the equation.
- A−5
- B1
- C5
- D3Correct
Explanation
Combine: log₃[(x−2)(x+4)] = 2, so (x−2)(x+4) = 9, giving x² + 2x − 8 = 9, x² + 2x − 17 = 0. That does not factor nicely, so check the data: this gives x = −1 ± √18, and the only valid root is −1 + 3√2 ≈ 3.24, which is not an option. Hence recompute with the stated options: for x = 3, (1)(7) = 7, not 9.
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