CA Foundation · Quantitative Aptitude · Probability
In a city, the probability that a randomly selected household has internet is 0.6 and that it has a television is 0.8. If these events are independent, what is the probability that a household has both internet and television?
Since having internet and having a television are independent events, the probability that a household has both equals the product of their individual probabilities: 0.6 × 0.8 = 0.48.
- A0.48Correct
- B1.40
- C0.14
- D0.26
Explanation
For independent events, P(A and B) = P(A) × P(B). Here, P(internet and TV) = 0.6 × 0.8 = 0.48. The distractor 1.40 is from adding instead of multiplying; 0.14 is from subtracting; 0.26 results from incorrect calculation of complement.
Did you get it right without looking?
One question tells you little. A timed set on Probability shows your real accuracy, how long you take and where you lose marks.
More Probability questions
- Two fair dice are rolled together. What is the probability that the sum of the numbers shown is greater than 10?
- The daily profit of Rahul's sweet shop in Indore is ₹2,000 with probability 0.3, ₹3,000 with probability 0.5 and ₹5,000 with probability 0.2…
- A manufacturing plant in Delhi produces widgets with a defect rate of 2%. Three widgets are selected at random and inspected. What is the pr…
- A bag contains 5 red balls, 3 blue balls and 2 green balls. If one ball is drawn at random, what is the probability that it is neither red n…
- Ravi estimates that a venture will give a profit of Rs 50,000 with probability 0.3, a profit of Rs 20,000 with probability 0.5, and a loss o…
- A box holds 5 red and 4 white balls. Three balls are drawn at random one after another without replacement. What is the probability that exa…