CA Foundation · Quantitative Aptitude · Measures of Central Tendency and Dispersion
In a moderately asymmetrical distribution, the mean is 36 and the median is 34. Using the empirical relationship among mean, median and mode, the mode is approximately:
The mode is approximately 30. For a moderately asymmetrical distribution, Mode = 3 × Median − 2 × Mean, which gives 3 × 34 − 2 × 36 = 102 − 72 = 30.
- A30Correct
- B32
- C38
- D40
Explanation
The empirical relation is Mode = 3 Median − 2 Mean. So Mode = 3(34) − 2(36) = 102 − 72 = 30. Choosing 40 comes from reversing the sign and computing 3 Mean − 2 Median = 108 − 68 = 40, which is wrong.
Did you get it right without looking?
One question tells you little. A timed set on Measures of Central Tendency and Dispersion shows your real accuracy, how long you take and where you lose marks.
More Measures of Central Tendency and Dispersion questions
- The daily number of orders received by a Jaipur shop on five days were 6, 10, 14, 18 and 22. What is the mean deviation about the arithmetic…
- For a moderately asymmetrical distribution, the mode is 24 and the arithmetic mean is 30. Using the empirical relationship between mean, med…
- Eight sorted observations are 10, 12, 15, 18, 22, 25, 30 and 34. Using Q1 = size of the (n+1)/4th item and Q3 = size of the 3(n+1)/4th item,…
- Two Chennai firms report monthly profits. Firm P: mean ₹80,000, SD ₹12,000. Firm Q: mean ₹50,000, SD ₹9,000. Which statement is correct?
- For the two unequal positive observations 4 and 16, which of the following relationships among the three means is correct?
- The marks obtained by five students in a test are 45, 52, 48, 55, and 50. What is the arithmetic mean of their marks?