Skip to content

CA Foundation · Quantitative Aptitude · Sets, Relations and Functions, Limits and Continuity

In a survey of 100 shareholders of a company, 60 hold equity shares, 45 hold preference shares and 15 hold neither. How many shareholders hold both equity and preference shares?

20 shareholders hold both types. Since 15 hold neither, 85 hold at least one type. Applying the union formula, 85 = 60 + 45 - x, so the intersection x equals 105 - 85 = 20.

  1. A15
  2. B20Correct
  3. C25
  4. D30

Explanation

Those holding at least one type = 100 - 15 = 85. Using n(E ∪ P) = n(E) + n(P) - n(E ∩ P): 85 = 60 + 45 - x, so x = 20. The option 25 comes from ignoring the 15 who hold neither and not using the union correctly.

Did you get it right without looking?

One question tells you little. A timed set on Sets, Relations and Functions, Limits and Continuity shows your real accuracy, how long you take and where you lose marks.

Practise Sets, Relations and Functions, Limits and ContinuityFree diagnostic mock

More Sets, Relations and Functions, Limits and Continuity questions