CA Foundation · Quantitative Aptitude · Sets, Relations and Functions, Limits and Continuity
Let f(x) = x² + 1 for x ≥ 0 and f(x) = 3x − 2 for x < 0. What is the value of f(−2) + f(3) − f(0)?
The value is 1. Using the correct rule for each point gives f(−2) = −8, f(3) = 10 and f(0) = 1, so −8 + 10 − 1 equals 1.
- A0Correct
- B1
- C−1
- D2
Explanation
f(−2) = 3(−2) − 2 = −8. f(3) = 9 + 1 = 10. f(0) = 0 + 1 = 1 since 0 uses the first rule. Sum: −8 + 10 − 1 = 1. Hence the value is 1, so the key is option B, not 0 as would come from using the wrong rule at x = 0.
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