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CA Foundation · Quantitative Aptitude · Measures of Central Tendency and Dispersion

The following frequency distribution shows the daily wages (in ₹) of 40 workers: 200-300 has 6 workers, 300-400 has 10 workers, 400-500 has 14 workers, 500-600 has 6 workers, 600-700 has 4 workers. What is the median wage?

With 40 workers, N/2 = 20, which falls in the 400-500 class where cumulative frequency before it is 16 and class frequency is 14. Median = 400 + (4/14) x 100 = ₹428.57.

  1. A₹414.29Correct
  2. B₹400.00
  3. C₹428.57
  4. D₹450.00

Explanation

N/2 = 20. Cumulative frequencies: 6, 16, 30, so the median class is 400-500. Median = 400 + ((20-16)/14) x 100 = 400 + 28.57 = 428.57. Using the lower limit 400 gives 428.57, so the correct option is ₹428.57; ₹414.29 comes from wrongly dividing by 28 instead of 14.

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