FRM Part II · FRM Exam Part II · Future Value and Exposure
A bank computes exposures for a counterparty at the 1-year horizon. Under a netting agreement, the portfolio value V is normal with mean USD 5 million and standard deviation USD 10 million. The 97.5% PFE is the 97.5th percentile of exposure max(V,0). Using z = 1.96 at 97.5%, and ignoring any collateral, what is the PFE and how does it compare to the PFE for the same portfolio if its mean were zero?
The 97.5% PFE is the mean plus 1.96 standard deviations: 5 + 19.6 = USD 24.6 million. With a zero mean it would be 19.6 million, so the positive mean raises PFE by USD 5 million.
- AUSD 24.6 million, which is USD 5 million higher than the zero-mean caseCorrect
- BUSD 14.6 million, which is USD 5 million lower than the zero-mean case
- CUSD 24.6 million, which is USD 5 million lower than the zero-mean case
- DUSD 19.6 million, equal to the zero-mean case
Explanation
The 97.5th percentile of V is 5 + 1.96×10 = 24.6 million, positive, so PFE equals 24.6. With zero mean it is 19.6, so the mean shift raises PFE by 5 million. Option 1 subtracts the mean, a sign error.
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