IAI Actuarial Core Principles · Actuarial Statistics · Hypothesis testing and goodness of fit
A chi-squared goodness-of-fit test is applied to 200 policies grouped into 6 cells, testing a Poisson distribution whose mean was estimated from the data. After merging cells so every expected count is at least 5, 5 cells remain. What are the degrees of freedom, and which critical value applies at 5% (chi-squared 5%: 1 df 3.841, 2 df 5.991, 3 df 7.815, 4 df 9.488)?
Degrees of freedom are the 5 remaining cells minus 1 minus the 1 estimated Poisson mean, giving 3. The 5% critical value for 3 degrees of freedom is 7.815. Forgetting to deduct the estimated parameter would wrongly give 4 degrees of freedom.
- A4 df; 9.488
- B3 df; 7.815Correct
- C2 df; 5.991
- D5 df; 11.07
- 1 df; 3.841
Explanation
Degrees of freedom = number of cells after merging minus 1 minus number of estimated parameters = 5 - 1 - 1 = 3. The 5% critical value for 3 df is 7.815. Using 4 df forgets the parameter estimated.
Did you get it right without looking?
One question tells you little. A timed set on Hypothesis testing and goodness of fit shows your real accuracy, how long you take and where you lose marks.
More Hypothesis testing and goodness of fit questions
- A Kolmogorov-Smirnov test compares an empirical distribution function with a fully specified continuous distribution. Which statement about …
- A test of independence is carried out on a table with 4 rows and 5 columns. How many degrees of freedom does the chi-squared test statistic …
- Which statement about the critical region of a most powerful test of a simple null hypothesis against a simple alternative, as given by the …
- In a test of whether residual signs from a fitted model are random, there are n1 = 10 positive and n2 = 10 negative residuals, with 6 runs o…
- Paired differences (after minus before) in monthly premium collection efficiency for 9 branches have mean 1.5 and sample standard deviation …
- A 2×3 contingency table has row totals 60 and 40, column totals 30, 50 and 20, and a grand total of 100. Under the null hypothesis of indepe…