CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations
A committee of 4 is to be formed from 5 finance executives and 4 marketing executives so that it contains exactly 2 from each department. How many such committees are possible?
There are 60 possible committees. Select 2 finance executives from 5 in 10 ways and 2 marketing executives from 4 in 6 ways, then multiply because the choices are independent: 10×6 = 60. The figure 126 ignores the condition of two from each department.
- A60Correct
- B36
- C126
- D30
Explanation
Choose 2 of 5 finance executives: 5C2 = 10. Choose 2 of 4 marketing executives: 4C2 = 6. Multiply: 10×6 = 60. The value 126 is 9C4, ignoring the exact-2 condition.
Did you get it right without looking?
One question tells you little. A timed set on Permutation and Combinations shows your real accuracy, how long you take and where you lose marks.
More Permutation and Combinations questions
- A committee of 3 members is to be chosen from 8 officers of a firm in Pune. In how many ways can the committee be formed?
- A Chennai firm must assign 4 different tasks to 4 different employees, one task per employee. In how many different ways can the assignment …
- If nP2 = 90, find the value of n, where n is a positive integer.
- From 6 men and 4 women, a panel of 5 persons is to be chosen so that it contains at least 2 women. How many panels are possible?
- A firm has 9 employees. It wants to divide them into three teams of 3 each, the teams being unlabelled and identical in function (no team is…
- A bank in Chennai issues a 3-character code: the first is a letter chosen from A, B, C, D, E, and the next two are digits from 0 to 9 with r…