CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations
A bank in Chennai issues a 3-character code: the first is a letter chosen from A, B, C, D, E, and the next two are digits from 0 to 9 with repetition allowed. How many codes are possible?
There are 500 codes. The letter can be chosen in 5 ways, and each of the two digit positions in 10 ways because repetition is allowed. Multiplying gives 5 × 10 × 10 = 500.
- A500Correct
- B450
- C150
- D50
Explanation
Letter: 5 ways. Each digit: 10 ways. Total = 5 × 10 × 10 = 500. The value 450 wrongly forbids repeated digits (5×9×10).
Did you get it right without looking?
One question tells you little. A timed set on Permutation and Combinations shows your real accuracy, how long you take and where you lose marks.
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