IAI Actuarial Core Principles · Economic Modelling · Ruin theory
A company's aggregate claims follow a compound Poisson process with λ = 2 per year. Each claim is ₹1 lakh with probability 0.5 and ₹2 lakh with probability 0.5 (units in lakhs). Premium rate c = 4 lakh per year. Which equation, in r, determines the adjustment coefficient, and what is true of the root?
The equation is 2 + 4r = e^r + e^{2r}, since λ times the claim MGF is 2 × (0.5e^r + 0.5e^{2r}). Checking r=0.5 gives the right side larger, so the positive root lies between 0 and 0.5.
- A2 + 4r = 1 e^{r} + 1 e^{2r}; R is the positive root, found by substituting y = e^{r} gives a quadratic with R = ln 2
- B2 + 4r = e^{r} + e^{2r}; the positive root is found by trial and lies between 0 and 0.5Correct
- C2 + 4r = 2 e^{1.5 r}; R = 0
- D4 + 2r = e^{r} + e^{2r}; R = ln 2
- 2 + 4r = 0.5 e^{r} + 0.5 e^{2r}; R = 0
Explanation
M_X(r) = 0.5e^r + 0.5e^{2r}, so λM_X(r) = e^r + e^{2r}. The equation is 2 + 4r = e^r + e^{2r}. At r=0 both sides equal 2; slopes are 4 versus 3 (mean claim 1.5 times 2), so the line is above initially. At r=0.5: LHS 4, RHS 1.6487+2.7183=4.367, so RHS exceeds LHS and the root lies between 0 and 0.5. Option 1 is not a quadratic solution and ln 2 gives LHS 3.77 vs RHS 2+4=6, wrong.
Did you get it right without looking?
One question tells you little. A timed set on Ruin theory shows your real accuracy, how long you take and where you lose marks.
More Ruin theory questions
- A compound Poisson surplus process has exponential claims with mean ₹50,000 and premium loading θ = 0.25. What is the probability of ultimat…
- In the classical compound Poisson surplus model, claims arrive at Poisson rate λ, individual claims are exponential with mean μ, and premium…
- For a compound Poisson surplus process with exponential claims of mean Rs 5 lakh and relative safety loading θ = 0.25, the ruin probability …
- In the compound Poisson model, Lundberg's inequality gives ψ(u) ≤ e^{-Ru}. If the insurer increases its premium loading while claim distribu…
- Which statement correctly distinguishes finite-time from ultimate ruin probability for a given surplus process?
- Under the Lundberg inequality psi(u) <= exp(-R u), an insurer with adjustment coefficient R=0.02 per Rs lakh holds initial surplus u=Rs 150 …