CMA Foundation · Fundamentals of Business Mathematics and Statistics · Arithmetic Progression and Geometric Progression
A company's annual profit was Rs 5,00,000 in year 1 and grows each year by a constant ratio. If the profit in year 3 was Rs 7,20,000, what was the profit in year 4?
Profit follows a geometric progression. Since 5,00,000 x r squared equals 7,20,000, r squared is 1.44 and the ratio is 1.2. The fourth-year profit is therefore 7,20,000 x 1.2, which equals Rs 8,64,000.
- ARs 8,64,000Correct
- BRs 8,20,000
- CRs 9,00,000
- DRs 8,40,000
Explanation
For a GP, ar^2 = 7,20,000 with a = 5,00,000, so r^2 = 1.44 and r = 1.2. Year 4 = 7,20,000 x 1.2 = Rs 8,64,000. Adding the year 2-3 difference (an AP view) would be a wrong method.
Did you get it right without looking?
One question tells you little. A timed set on Arithmetic Progression and Geometric Progression shows your real accuracy, how long you take and where you lose marks.
More Arithmetic Progression and Geometric Progression questions
- A firm's sales grew by 20% in the first year and by 80% in the second year. What is the equivalent constant yearly growth rate over the two …
- In an arithmetic progression the 4th term is 17 and the 9th term is 42. What is the 15th term?
- A ball is dropped from a height of 16 m and after each bounce rises to half of the previous height. Taking the initial drop plus all subsequ…
- A firm's sales grew by 20% in one year and by 80% in the next year. What constant yearly growth factor would give the same two-year growth, …
- Three numbers are in GP with a product of 216 and a sum of 21. If the common ratio is greater than 1, what is the largest number?
- A Jaipur handicraft unit produced 300 pieces in January and increases output by 20 pieces every month. What is its total production for the …