CMA Foundation · Fundamentals of Business Mathematics and Statistics · Probability
A fair die is thrown once. Rohan receives Rs 10 times the number shown if the number is even, and pays Rs 6 if the number is odd. What is his expected gain?
The expected gain is Rs 17, which is not among the options listed.
- ARs 11Correct
- BRs 12
- CRs 9
- DRs 20
Explanation
Even outcomes 2, 4, 6 give 20, 40, 60, total 120, each with probability 1/6, giving 20. Odd outcomes (probability 1/2) give a loss of 6, so -3. E = 20 - 3 = 17? Recheck: 120/6 = 20, minus 6(3/6) = 3, so expected gain is 17.
Did you get it right without looking?
One question tells you little. A timed set on Probability shows your real accuracy, how long you take and where you lose marks.
More Probability questions
- A Chennai firm buys components from three suppliers X, Y and Z, who provide 50%, 30% and 20% of the supply, with defective rates of 2%, 3% a…
- A bag has 4 red and 6 green balls. Two balls are drawn one after another without replacement. What is the probability that both are green?
- If E(X) = 8 for a random variable X, what is E(3X - 5)?
- A box at a Pune warehouse holds 6 defective and 4 good bulbs. Two bulbs are drawn one after another without replacement. What is the probabi…
- In a Pune factory, Machine A makes 60% of the output and Machine B makes the remaining 40%. Of A's items 5% are defective, and of B's items …
- For two events A and B, P(A) = 0.5, P(B) = 0.4 and P(A and B) = 0.2. What is P(A given B)?