IAI Actuarial Core Principles · Actuarial Statistics · Central limit theorem
A fair six-sided die is rolled 120 times. Using a normal approximation with no continuity correction, what is the approximate probability that the total of the 120 rolls exceeds 441? (Each roll has mean 3.5 and variance 35/12; Φ(1.0)=0.8413, Φ(1.5)=0.9332, Φ(2.0)=0.9772.)
The total has mean 420 and sd about 18.7, so 441 lies roughly one standard deviation above the mean. The upper-tail probability, using the given table value, is 1−0.8413 = 0.1587. Using 0.8413 would give the lower tail instead.
- A0.0228
- B0.0668
- C0.1587Correct
- D0.8413
- 0.9332
Explanation
Total mean = 120×3.5 = 420. Total variance = 120×35/12 = 350, so sd ≈ 18.71. z = (441−420)/18.71 ≈ 1.12, so with the given table the nearest value is about 1.0 sd, giving 1−0.8413 = 0.1587. Option 0.8413 is the lower tail, which is the wrong direction.
Did you get it right without looking?
One question tells you little. A timed set on Central limit theorem shows your real accuracy, how long you take and where you lose marks.
More Central limit theorem questions
- X follows a Poisson distribution with mean 36. Using the normal approximation with continuity correction, the approximate value of P(X ≤ 30)…
- The daily claim amounts at an Indian insurer's branch are independent with mean Rs 5,000 and standard deviation Rs 2,000. Using the central …
- The sum S of 50 independent Poisson(2) claim counts is approximated by a normal distribution with continuity correction. For which statement…
- X follows a Binomial(100, 0.5) distribution. Using a normal approximation with continuity correction, what is the approximate value of P(X ≤…
- The sample mean X̄ of n independent observations from a skewed distribution with mean μ and variance σ² is approximately normal for large n.…
- X ~ Binomial(100, 0.4). Using a normal approximation with continuity correction, which expression approximates P(X ≤ 35)? Here sd = √24 ≈ 4.…