Skip to content

FRM Part I · FRM Exam Part I · External and Internal Credit Ratings

A one-year transition matrix has three states: A, B, and D (default, absorbing). From A: A 0.90, B 0.08, D 0.02. From B: A 0.10, B 0.80, D 0.10. Assuming a time-homogeneous Markov chain, what is the two-year cumulative default probability for an issuer currently rated A?

The two-year cumulative default probability is 4.6%. It sums year-one default of 2%, staying in A then defaulting (0.90×0.02=1.8%), and moving to B then defaulting (0.08×0.10=0.8%). Omitting any path gives an incorrect figure.

  1. A0.0400
  2. B0.0360
  3. C0.0260
  4. D0.0460Correct

Explanation

Two-year PD = P(A→A)·P(A→D) + P(A→B)·P(B→D) + P(A→D)·1 = 0.90×0.02 + 0.08×0.10 + 0.02 = 0.018 + 0.008 + 0.02 = 0.046. Doubling 0.02 gives 0.04, which omits the migration paths. The 0.0260 option omits the first-year default of 0.02 (sum of 0.018+0.008).

Did you get it right without looking?

One question tells you little. A timed set on External and Internal Credit Ratings shows your real accuracy, how long you take and where you lose marks.

More External and Internal Credit Ratings questions