IAI Actuarial Core Principles · Actuarial Statistics · Linear regression models
A regression with an intercept and two covariates is fitted to n = 20 observations. The estimated variance σ̂² = 4 and the relevant diagonal element of (XᵀX)⁻¹ for β₁ is 0.25. Given β̂₁ = 2.5, what is the value of the t statistic for testing H₀: β₁ = 0?
The t statistic is 2.50. The estimated variance of β̂₁ is σ̂² times the diagonal element, 4 × 0.25 = 1, so the standard error is 1. Dividing the estimate 2.5 by 1 gives 2.5, tested on 17 degrees of freedom.
- A1.25
- B2.50Correct
- C5.00
- D10.00
- 2.00
Explanation
Var(β̂₁) = σ̂² × 0.25 = 4 × 0.25 = 1, so the standard error is 1. The t statistic is 2.5/1 = 2.5, compared with t on 17 degrees of freedom. Using 0.25 as the standard error gives 10, which is a mistake.
Did you get it right without looking?
One question tells you little. A timed set on Linear regression models shows your real accuracy, how long you take and where you lose marks.
More Linear regression models questions
- In a simple linear regression fitted to 12 observations, the total sum of squares is 500 and the residual sum of squares is 125. What is the…
- A regression with an intercept and 3 explanatory variables is fitted to n = 24 observations. The total sum of squares is 480 and the residua…
- A model with an intercept and two explanatory variables is fitted to n = 24 observations by least squares. The residual sum of squares is 90…
- A regression through five points gives residual sum of squares 18 for the model y = α + βx + ε with errors N(0, σ²). What is the unbiased es…
- A simple linear regression with an intercept is fitted to n = 12 observations. The residual sum of squares is 90 and the leverage of one obs…
- In a simple linear regression fitted to 12 observations, the total sum of squares is 480 and the regression (explained) sum of squares is 36…