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CA Foundation · Quantitative Aptitude · Equations

Anita mixes two varieties of tea costing ₹300 per kg and ₹400 per kg to get 20 kg of a mixture worth ₹350 per kg. How many kg of the ₹400 variety does she use?

She uses 10 kg of the ₹400 variety. Letting that quantity be y gives 300(20 − y) + 400y = 7,000, so 100y = 1,000 and y = 10. The mixture mean of ₹350 lies midway between the two prices, so equal quantities are needed.

  1. A8 kg
  2. B12 kg
  3. C10 kgCorrect
  4. D15 kg

Explanation

Let the ₹400 tea be y kg, so the ₹300 tea is (20 − y) kg. Then 300(20 − y) + 400y = 350 × 20 = 7,000, so 6,000 + 100y = 7,000 and y = 10. Check: 3,000 + 4,000 = 7,000. Choosing 12 or 8 would give mean prices of ₹360 or ₹340, not ₹350.

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