CMA Final · Strategic Cost Management · Business Application of Maxima and Minima
Annual demand for a component is 3,600 units, ordering cost is Rs 100 per order and carrying cost is Rs 2 per unit per year. Using calculus on total annual cost T(Q) = (3,600/Q)(100) + (Q/2)(2), the cost-minimising order quantity Q and minimum total cost are:
Total cost is 360,000 divided by Q plus Q. Differentiating and equating to zero gives Q squared equal to 360,000, so the order quantity is 600 units. Ordering and carrying costs are each Rs 600, so minimum total cost is Rs 1,200.
- AQ = 600, T = Rs 1,200Correct
- BQ = 600, T = Rs 600
- CQ = 360, T = Rs 1,360
- DQ = 300, T = Rs 1,500
Explanation
T = 360,000/Q + Q. dT/dQ = -360,000/Q^2 + 1 = 0 gives Q^2 = 360,000, so Q = 600. T = 360,000/600 + 600 = 600 + 600 = 1,200. At the optimum ordering and carrying costs are equal. Rs 600 shows only one component of cost.
Did you get it right without looking?
One question tells you little. A timed set on Business Application of Maxima and Minima shows your real accuracy, how long you take and where you lose marks.
More Business Application of Maxima and Minima questions
- A Pune firm's total cost function is C(x) = 2x² + 40x + 5,000 (in rupees), where x is units produced per week. At what output is the average…
- A firm's total cost function is C(x) = 2x^2 - 40x + 500 (in rupees thousand), where x is units produced in hundreds. At what output x is tot…
- A manufacturer sells x units at a price p = 120 - 0.5x rupees per unit. Variable cost is Rs 40 per unit, and fixed cost is Rs 2,000. What ou…
- A firm's profit function is P(x) = -x³ + 12x² + 60x - 100 for x ≥ 0 (x in hundreds of units, P in Rs thousands). At which output does profit…
- A firm's total cost function is C(x) = 2x^2 - 40x + 500, where x is units produced per day. At what output is total cost minimised?
- Demand for a product is p = 200 - 2x (rupees per unit) and total cost is C(x) = 20x + 400. At what output does profit reach its maximum, and…