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CMA Foundation · Fundamentals of Business Mathematics and Statistics · Measures of Central Tendency and Dispersion

For a distribution, the mean is 60, the standard deviation is 15 and Karl Pearson's coefficient of skewness is -0.4. Assuming the empirical relation among mean, median and mode holds, the median of the distribution is:

The median is 62. From the skewness of -0.4 and standard deviation 15, mean minus mode is -6, so the mode is 66. Using Mode = 3 Median - 2 Mean, the median is (66 + 2 × 60)/3 = 62.

  1. A58
  2. B62Correct
  3. C63
  4. D66

Explanation

Sk = (Mean - Mode)/SD gives -0.4 = (60 - Mode)/15, so 60 - Mode = -6 and Mode = 66. Empirical relation: Mode = 3Median - 2Mean, so Median = (66 + 120)/3 = 62. Choosing 66 reports the mode, and 58 comes from taking the mode as 54 (wrong sign).

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