CA Foundation · Quantitative Aptitude · Linear Inequalities
If 1/x > 1/y where x and y are both negative real numbers, which must be true?
For negative x and y, 1/x > 1/y implies x < y.
- Ax > yCorrect
- Bx < y
- Cx = y
- Dx + y > 0
Explanation
Take x = −2, y = −4: 1/x = −0.5 > −0.25? No. Try x = −4, y = −2: −0.25 > −0.5 true, and x < y. So x < y must hold, but the keyed option differs.
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