CA Foundation · Quantitative Aptitude · Linear Inequalities
If 5 − 2x ≥ 3x − 20 and x is a natural number, how many values of x are possible?
Five values are possible. Solving 5 − 2x ≥ 3x − 20 gives x ≤ 5, and the natural numbers up to and including 5 are 1, 2, 3, 4 and 5. The boundary value 5 is included because the inequality is non-strict.
- A4
- B6
- C5Correct
- DInfinitely many
Explanation
5 − 2x ≥ 3x − 20 gives 25 ≥ 5x, so x ≤ 5. Natural numbers are 1, 2, 3, 4, 5, which is 5 values. Choosing 4 would wrongly exclude the boundary value 5, which is allowed by the non-strict inequality.
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