Skip to content

IAI Actuarial Core Principles · Risk Modelling and Survival Analysis · Compound distributions and their applications in risk modelling

If S is compound Poisson with parameter lambda and the claim size X has moment generating function M_X(t), which expression gives the MGF of S?

The MGF of a compound Poisson variable is exp{lambda(M_X(t) - 1)}. It comes from substituting the log of the claim-size MGF into the Poisson MGF, because M_S(t) equals M_N evaluated at ln M_X(t).

  1. Aexp{lambda(M_X(t) - 1)}Correct
  2. Blambda(M_X(t) - 1)
  3. Cexp{lambda M_X(t)}
  4. D(1 - lambda + lambda M_X(t))
  5. exp{lambda(e^t - 1)} M_X(t)

Explanation

M_S(t)=M_N(ln M_X(t)). With Poisson M_N(u)=exp{lambda(e^u-1)}, substituting e^u=M_X(t) gives exp{lambda(M_X(t)-1)}. Option 3 resembles a Bernoulli-type form and is wrong.

Did you get it right without looking?

One question tells you little. A timed set on Compound distributions and their applications in risk modelling shows your real accuracy, how long you take and where you lose marks.

More Compound distributions and their applications in risk modelling questions