IAI Actuarial Core Principles · Risk Modelling and Survival Analysis · Compound distributions and their applications in risk modelling
If S is compound Poisson with parameter lambda and the claim size X has moment generating function M_X(t), which expression gives the MGF of S?
The MGF of a compound Poisson variable is exp{lambda(M_X(t) - 1)}. It comes from substituting the log of the claim-size MGF into the Poisson MGF, because M_S(t) equals M_N evaluated at ln M_X(t).
- Aexp{lambda(M_X(t) - 1)}Correct
- Blambda(M_X(t) - 1)
- Cexp{lambda M_X(t)}
- D(1 - lambda + lambda M_X(t))
- exp{lambda(e^t - 1)} M_X(t)
Explanation
M_S(t)=M_N(ln M_X(t)). With Poisson M_N(u)=exp{lambda(e^u-1)}, substituting e^u=M_X(t) gives exp{lambda(M_X(t)-1)}. Option 3 resembles a Bernoulli-type form and is wrong.
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