CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations
In how many ways can 9 different books be divided equally among 3 students, Asha, Bimal and Charu, so that each gets 3 books?
The books can be distributed in 1680 ways. Since the three students are distinct, choose 3 books for the first in 9C3 = 84 ways, 3 of the remaining 6 for the second in 20 ways, and the rest go to the third. 84×20 = 1680.
- A84
- B280
- C1680Correct
- D504
Explanation
Asha chooses 3 of 9: 9C3 = 84. Bimal chooses 3 of remaining 6: 6C3 = 20. Charu gets the last 3: 1. Total = 84×20 = 1680. The value 280 = 1680/6 applies only if the groups were unlabelled.
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